Answer:
t = 5.05 s
Explanation:
This is a kinetic problem.
a) to solve it we must fix a reference system, let's use a fixed system on the floor where the height is 0 m
b) in this system the equations of motion are
y = v₀ t + ½ g t²
where v₀ is the initial velocity that is v₀ = 0 and g is the acceleration of gravity that always points towards the center of the Earth
e) y = 0 + ½ g t²
t = √ (2y / g)
t = √(2 125 / 9.8)
t = 5.05 s
For the First answer, It would be "A"
The for the next one the answer is "C"
I hope this helps. :)
Answer:
13.02 m/s the velocity and 86.92 degrees the direction relative to ground
Explanation:
We need to add velocities in vector addition to find the resultant velocity "" of the balloon (the 13 m/s and the 0.7 m/s).
The velocities are at 90 degrees from each other (one pointing up and the other to the East). Notice from the attached image that the resultant velocity vector (picture in red) is actually the hypotenuse of a right angle triangle.
So we use Pythagoras to find the length (magnitude) of the resultant velocity vector:
we can round the answer to 13.02 m/s
Now we need to find the angle that this new vector makes with the ground by using the definition of tangent of an angle that relates the two quantities that we just added:
So we round it to 86.92 degrees
Mass is the area an object takes up. Like a box on the floor that box has a mass for it is taking up an area