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goldfiish [28.3K]
3 years ago
15

What type of polynomial is this and what is its degree? 5b3 - 3 + 6b

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
3 0

Answer:

3rd degree trinomial

Step-by-step explanation:

the highest power is 3 and there are 3 terms so its a 3rd degree trinomial

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PLEASE HELP ME OUT!!!
DedPeter [7]

Answer:

20/3  or  6.67  or  6 \frac{2}{3}  (any of these are correct)

Step-by-step explanation:

Volume of triangular pyramid formula is V = 1/3 * base area * height

V = 1/3 * 5 * 4 = 20/3

20/3  or  6.67  or  6 \frac{2}{3}

4 0
2 years ago
Product A is an 8-oz. bottle of cough medicine that sells for$1.36. Product B is a 16- oz. bottle of cough medicine that costs $
Arada [10]

Answer:

The $3.20 one

Step-by-step explanation:

The $3.20 one is cheaper because you get more.

6 0
3 years ago
Consider these functions f(x)=3x-7 g(x)=x+1/x-1 what is the of f(g(3)) answer
JulijaS [17]

Answer:

\boxed{-1}

.

Step-by-step explanation:

g(3) = \frac{3 + 1}{3 - 1}  = 2

f(g(3)) = 3(2) - 7 = -1

3 0
2 years ago
I need help how to solve it DON'T give me the Answer plz ....!!!
stiks02 [169]
F is the answer lol BTW it's f
6 0
3 years ago
According to a recent​ survey, the population distribution of number of years of education for​ self-employed individuals in a c
creativ13 [48]

Answer:

a) X: number of years of education

b) Sample mean = 13.5, Sample standard deviation = 0.4

c) Sample mean = 13.5, Sample standard deviation = 0.2

d) Decrease the sample standard deviation

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 13.5 years

Standard deviation,σ = 2.8 years

a) random variable X

X: number of years of education

Central limit theorem:

If large random samples are drawn from population with mean \mu and standard deviation \sigma, then the distribution of sample mean will be normally distributed with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

b) mean and the standard for a random sample of size 49

\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{49}} = 0.4

c) mean and the standard for a random sample of size 196

\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{196}} = 0.2

d) Effect of increasing n

As the sample size increases, the standard error that is the sample standard deviation decreases. Thus, quadrupling sample size will half the standard deviation.

7 0
3 years ago
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