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2 years ago

What type of polynomial is this and what is its degree? 5b3 - 3 + 6b

Mathematics

1 answer:

Dmitry_Shevchenko [17]2 years ago

3 0

Answer:

3rd degree trinomial

Step-by-step explanation:

the highest power is 3 and there are 3 terms so its a 3rd degree trinomial

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PLEASE help with 12 :))

Kitty [74]

The answer would be x<-6

7 0

3 years ago

PLEASE HELP!!!

jonny [76]

Answer:

Point A is located at (8,6)

Step-by-step explanation:

As I said in the last answer I did for u, (8,6) basically means x is 8 and y is 6. If you see A, A is located on 8 for x and 6 for y. the others are incorrect such as B because B is on the 8 for x but the y is on 8. hope this helps '∆'

7 0

2 years ago

Read 2 more answers

Just question 4 please. I NEED TO SHOW MY WORK AS TO HOW I GOT THE ANSWER!!!! Stuck someone please help?!!

Galina-37 [17]

Well first you wanna see how many pints are in 3 quarts, which is 6 because there are 2 pints in a quart.

3 0

3 years ago

3. Is XY Tangent to circle Z? Y 12 X (20 Z 18

Ratling [72]

Answer:

XY is a tangent

Step-by-step explanation:

Given

$XY = 12$

$WY = 20$

$WZ = 8$

Required

Is XY a tangent?

XY is a tangent if:

$WY^2 = XY^2 + WX^2$

Because XY should make a right angle at point X with the circle

Where

$WX = 2 * WZ$

So, we have:

$WY^2 = XY^2 + WX^2$

$WY^2 = XY^2 + (2*WZ)^2$

$WY^2 = XY^2 + (2WZ)^2$

$WY^2 = XY^2 + 4WZ^2$

This gives:

$20^2 = 12^2 + 4*8^2$

$400 = 144 + 256$

$400 = 400$

Yes, XY is a tangent

4 0

2 years ago

Write the expressions without using log. Can someone please help with this?

goldenfox [79]

$\bf \textit{logarithm of factors}\\\\
log_{{ a}}(xy)\implies log_{{ a}}(x)+log_{{ a}}(y)
\\\\\\
\textit{Logarithm of rationals}\\\\
log_{{ a}}\left( \frac{x}{y}\right)\implies log_{{ a}}(x)-log_{{ a}}(y)
\\\\\\
\textit{Logarithm of exponentials}\\\\
log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)\\\\
-------------------------------$

$\bf log(m^3n)\implies log(m^3)+log(n)\implies 3log(m)+log(n)
\\\\\\
\boxed{3k+v}
\\\\\\
log\left(\cfrac{m}{n^3} \right)\implies log(m)-log(n^3)\implies log(m)-3log(n)
\\\\\\
\boxed{k-3v}$

6 0

3 years ago