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3 years ago

Determine the intercepts of the line.

Mathematics

1 answer:

Strike441 [17]3 years ago

3 0

Answer:

Step-by-step explanation:

An intercept is where the line hits the axis.

Lets start with x. The x intercept is always going to be what x equals when y = 0. So we know the second value of the x intercept is going to be 0, because the second value is y. The line hits the x axis at -1.2, so the x intercept is -1.2, 0

The y intercept it what y equals when x equals 0. So the first value is going to be 0, to represent x. The line hits the y intercept at the point 0, -0.7.

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The circumference of a dime is 56.52 mm find the diameter

Snowcat [4.5K]

Circumference= pi × d
So
d= circumference/pi
So to find out the diameter, just do 56.52/pi= 17.99mm (2 d.p.)

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3 years ago

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To cover A rectangle region of her yard penny needs atleast 170.5 square feet of sod. The length of the region is 15.5 feet. Wha

stiks02 [169]

The area needed is at least 170.5 ft².

Let w = the width of the rectangular area.
Because the length is 15.5 ft, therefore the calculated area should be at least 170.5 ft². That is
(15.5 ft)*(w ft) ≥ 170.5 ft²
w ≥ 170.5/15.5
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3 years ago

Find an equation of the line that passes through the points (-0.5,0.75) and (0.75,-0.5)

Keith_Richards [23]

The equation of the line can be shown using the slope intercept form that is

y= mx+b

where m is the slope and b is the y intercept

So firstly we have to find the value of slope m

To find the value of slope m we apply the formula

$m= \frac{( y_{2} - y_{1})}{( x_{2} - x_{1})}$

So we can plug the values using the two given points

(-0.5,0.75) and (0.75,-0.5)

$m= \frac{(-0.5-0.75) }{(0.75-(-0.5))} = \frac{-1.25}{1.25} = -1$

So m = -1

Plug m=-1 in the equation we get

y= -1x +b

Now we have to find the value of b

to find the value of b , we plug any one pint in the equation

0.75 = -1(-0.5) +b

0.75 = 0.5 +b

Subtract 0.5 from both sides

0.25 = b

b= 0.25

Now plug the value of b , in the equation

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y = -1x +0.25

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3 years ago

PLEASE HELP!!!!!

USPshnik [31]

X = 25 x Cos(18 deg)

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Explain how to modify the graphs of f(x) and g(x) to graph the solution set to the following system of inequalities. How can the

Norma-Jean [14]

The graphs of f(x) and g(x) are transformed function from the function y = x^2

The set of inequalities do not have a solution

<h3>How to modify the graphs</h3>

From the graph, we have:

$f(x) = x^2 -3$ and $g(x) = -x^2 +2$

To derive y < x^2 - 3, we simply change the equality sign in the function f(x) to less than.

To derive y > x^2 + 2, we perform the following transformation on the function g(x)

Shift the function g(x) down by 2 units
Reflect across the x-axis
Shift the function g(x) down by 3 units
Change the equality sign in the function g(x) to greater than

<h3>How to identify the solution set</h3>

The inequalities of the graphs become

y < x^2 - 3 and y > x^2 + 2

From the graph of the above inequalities (see attachment), we can see that the curves of the inequalities do not intersect.

Hence, the set of inequalities do not have a solution