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Paladinen [302]
4 years ago
13

Write a quadratic function whose zeros are -3 and -4

Mathematics
1 answer:
andreev551 [17]4 years ago
6 0

Answer:

  f(x) = (x -(-3))(x -(-4))

Step-by-step explanation:

The function can be written as the product of binomial terms whose values are zero at the given zeros.

  (x -(-3)) is one such term

  (x -(-4)) is another such term

The product of these is the desired quadratic function. In the form easiest to write, it is ...

  f(x) = (x -(-3))(x -(-4))

This can be "simplified" to ...

  f(x) = (x +3)(x +4) . . . . simplifying the signs

  f(x) = x^2 +7x +12 . . . . multiplying it out

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RUDIKE [14]
The answer choice is C, because the problem is asking for the outcome of either one of the answers. Then you just add them together and the answer is 0.5+0.3=0.8. Hope this helped!
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4 years ago
1. Name three collinear points.
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J,G,I

Step-by-step explanation:

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8 0
3 years ago
Please help 50 points
dexar [7]

Answer:

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3+8

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Step-by-step explanation:

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3 years ago
Read 2 more answers
What is 2(9x-1)+7(x+6)=-60
Harman [31]
2(9x-1)+7(x+6)=-60
Reorder the terms in parentheses
+(+18x-2)+7*(x+6)=-60
Remove unnecessary parentheses
+18x-2+7*(+x+6)=-60
Reorder the terms in parentheses
+18x-2+(+7x+42)=-60
Remove unnecessary parentheses
+18x-2+7x+42=-60
We move all terms containing x to the left and all other terms to the right
+18x+7x=-60+2-42
We simplify left and right side of the equation
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We divide both sides of the equation by 25 to get x
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6 0
4 years ago
If 2(a^2+b^2)=(a+b)^2 then, <br> &gt;a+b=0,<br> &gt;ab=0,<br> &gt;a=b,<br> &gt;2a=b
Tasya [4]

Answer:

2·(a^2 + b^2) = (a + b)^2

2·a^2 + 2·b^2 = a^2 + 2·a·b + b^2

a^2 + b^2 = 2·a·b

a^2 - 2·a·b + b^2  = 0

(a - b)^2 = 0

a = b


7 0
3 years ago
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