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insens350 [35]
3 years ago
7

Is 1/2 = to 2/4 or is 1/2 greater than 1/4

Mathematics
1 answer:
REY [17]3 years ago
6 0
It's both? it's equal to 2/4 and greater than 1/4
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jonny [76]

Answer:

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Step-by-step explanation:

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3 years ago
James sees a truck at the dealership for $28,000
Lera25 [3.4K]

Answer:

The correct answer is C. $28,200.

Step-by-step explanation:

Given that James saw a truck at the dealership for $ 28,000 base price, $ 1,300 premium interior, $ 1,200 navigation touch-screen, and $ 1,700 smart traffic sensors, if his current vehicle is worth $ 5,000 and he's offered a 60% trade-in rate, to determine what is the total cost of the car after the $ 1,000 destination fee, the following calculation must be made:

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Therefore, the total cost of the car after the $ 1,000 destination fee is $ 28,200.

3 0
3 years ago
An amount of $8,000 is invested at a simple interest rate of 1.5%. What is the total amount after 3 years?
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6 0
3 years ago
Read 2 more answers
Assume that adults have IQ scores that are normally distributed with a mean of 96 and a standard deviation of 15.7. Find the pro
astraxan [27]

Answer:

4.05% probability that a randomly selected adult has an IQ greater than 123.4.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 96, \sigma = 15.7

Probability that a randomly selected adult has an IQ greater than 123.4.

This is 1 subtracted by the pvalue of Z when X = 123.4. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{123.4 - 96}{15.7}

Z = 1.745

Z = 1.745 has a pvalue of 0.9595

1 - 0.9595 = 0.0405

4.05% probability that a randomly selected adult has an IQ greater than 123.4.

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