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Ivahew [28]
2 years ago
14

Wilt Chamberlin holds the record for the highest number of points scored in a single NBA basketball game. Chamberlin scored 100

points for Philadelphia against the New York Knicks on March 2, 1962. Chamberlain made a total of 64 baskets consisting of field goals (worth 2 points) and foulshots (worth 1 point). Find the number of field goals and the number of foul shots that chamberlain mad
Mathematics
1 answer:
Genrish500 [490]2 years ago
3 0

Answer:

field goals = 36,  foul shots = 28.

Step-by-step explanation:

Given:

Chamberlin scored 100 points.

Chamberlain made a total of 64 baskets consisting of field goals and foulshots.

Each field goal worth = 2 points

Each foulshot  worth =  1 points

Question asked:

Find the number of field goals and the number of foul shots that chamberlain made ?

Solution:

Let number of field goals = x

<u>As total of 64 baskets, he made:</u>

Then number of foul shots = 64-x

Now, total points, he scored is given 100,

<u><em>Number of field goals </em></u>\times<u><em> 2 + Number of foul shots </em></u>\times<u><em> 1 = 100</em></u>

x\times2+(64-x)\times1=100\\2x+64-x=100\\x+64=100

Subtracting both sides by 64

x+64-64=100-64\\x=36

Number of field goals = x = 36

Then number of foul shots = 64-x = 64 - 36 = 28

Therefore, 36 field goals and 28 foul shots made by chamberlain.

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3 years ago
3 1⁄2 kilometers = hectometers
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Step-by-step explanation:

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3 years ago
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Community college students conduct a survey at their college. They ask "Do you plan to transfer to a university to pursue a bacc
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Answer:

0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697

0.8 + 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.903

The 99% confidence interval would be given by (0.697;0.903)

And the best option is : 0.697 to 0.903

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

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Solution to the problem

For this case the conditions we have the conditions to assume a normal distribution for the population proportion since:

np=100*0.8=80 >10 , n(1-p) = 10*(1-0.8) =20 >10

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

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The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The estimated proportion is given by \hat p =\frac{80}{100} =0.8. If we replace the values obtained we got:

0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697

0.8 + 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.903

The 99% confidence interval would be given by (0.697;0.903)

And the best option is : 0.697 to 0.903

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Answer:

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Step-by-step explanation:

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