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Stolb23 [73]
3 years ago
15

A Student select a marble from a bag, keeps it and select another. The bag contains 5 Green marbles 4 black marbles and 2 blue m

arbles. Find the probability of selecting a green marble on the first trial and a black marble on the second trial.
Mathematics
1 answer:
Serga [27]3 years ago
7 0

Answer:

Yes because yes.

Step-by-step explanation:

Y + e + s = Yes

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9/10 divided by 3/12
Find the least common multiple
54/60 divided by 15/60
Flip the second fraction and transition from division to multipication
54/60*60/15
Final answer: 3.6 or 3 3/5
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From the table below create an equation.
Bond [772]

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Step-by-step explanation:

2,4 ,10,12,19,36.5,40

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A box of crackers weighs 11 1/4 ounces. The estimated serving is 3/4 ounce. How many servings are in the box?
eimsori [14]
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Read 2 more answers
Use quadratic formula to solve 1-6x^2-x​
eduard

Answer:

(3x-1)(2x+1)

Step-by-step explanation:

1-6x^2-x=0

-6x^2-x+1=0

6x^2+x-1=0

6x^2+(3-2)x-1=0

6x^2+3x-2x-1=0

3x(2x+1)-1(2x+1)=0

(3x-1)(2x+1)=0

So the factor is (3x-1)(2x+1)

6 0
3 years ago
Theorem: A line parallel to one side of a triangle divides the other two proportionately.
Elenna [48]

Answer:

Segment BF = 16 is true.

Step-by-step explanation:

Since, DE is parallel to BC, so DE will divide AB and AC proportionally.

Hence,

\frac{AE}{EC}  = \frac{AD}{DB}

⇒  \frac{12}{18}  = \frac{6}{DB} 

{Since, given that AE = 12, EC = 18 and AD = 6}

⇒ BD = 9.

Again, since, EF is parallel to AB, so EF will divide BC and AC proportionally.

Hence, \frac{CE}{AE}  = \frac{FC}{BF}

⇒ \frac{18}{12}  = \frac{24}{BF}   

{Since, given that AE = 12, EC = 18 and FC= 24}

⇒ BF = 16.

Therefore, segment BF = 16 is true. (Answer)

3 0
3 years ago
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