A square has an area that is less than 100m2. What is reasonable range for the graph of the square sides

The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of 20. Each d

liberstina [14]

Answer: 0.0516

Step-by-step explanation:

Given : The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of $\lambda=20$ .

The probability mass function for Poisson distribution:- $P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}$

For x= 15 and $\lambda=20$ , we have

$P(X=x)=\dfrac{e^{-20}(20)^{15}}{15!}=0.0516488535318\approx0.0516$

Hence, the probability that exactly 15 defective components are produced in a particular day = 0.0516

7 0

3 years ago

If the circle below is cut from the square of plywood below, how many square inches of plywood would be left over? Use π = 3.14,

Elis [28]

Answer:

86in²

Step-by-step explanation:

Find the complete question attached

Area of the circle = πr²

Area of the square = L²

Length of the side of the square

r is the radius of the circle

r = L/2 = 20/2 =10in

Given

Length of the side of the circle = 20in

Area of the square = 20²

Area of the square = 400in²

Area of the circle =π(10)²

Area of the circle = 3.14(100)

Area of the circle= 314in²

Amount of plywood left over = 400in²-314in² = 86in²

8 0

3 years ago

(35 + 5)[16 + (12 divide 4)]

nadezda [96]

Answer:

59

Step-by-step explanation:

8 0

3 years ago

Please help! ive been stuck on this for so long and i just keep getting frustrated can someone help walkme through this?

bagirrra123 [75]

For firework launched from height 100ft with initial velocity 150ft/sec, equation made is correct

(a) equation will be $h(t) = -16t^2+150t+100$

(b) Now we have to see when it will land. At land or ground level height h will be equal to 0. So simply plug 0 in h place in equation made in part (a)

$0 = -16t^2 + 150t + 100$

Now we have to solve this quadratic. We will use quadratic formula method to solve this equation.

$t = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$

a = -16, b = 150, c = 100.

Plugging these values in quadratic formula we get

$t = \frac{-150 \pm \sqrt{150^2-4(-16)(100)}}{2(-16)}$

$t = \frac{-150 \pm \sqrt{22500+6400}}{-32}$

$t = \frac{-150 \pm \sqrt{28900}}{-32}$

$t = \frac{-150+170}{-32} = \frac{20}{-32} = -0.625$

time cannot be negative so we will drop this answer

then $t = \frac{-150-170}{-32} = \frac{-320}{-32} = 10$

So 10 seconds is the answer for this

(c) To make table simply plug various value for t like t =0, 2, 4, 6, 8 till 10. Plug values in equation mad in part (a) and find h value for each t as shown

For t =0 seconds, $h = -16(0)^2+150(0)+100 = 100 feet$

For t =2 seconds, $h = -16(2)^2+150(2)+100 =336 feet$

For t =4 seconds, $h = -16(4)^2+150(4)+100 = 444 feet$

For t =6 seconds, $h = -16(6)^2+150(6)+100 = 424 feet$

For t =8 seconds, $h = -16(8)^2+150(8)+100 = 276 feet$

For t =10 seconds, $h = -16(10)^2+150(10)+100 = 0 feet$

(d) Axis of symmetry is given by formula

$x = \frac{-b}{2a}$

$t = \frac{-150}{2(-16)} =\frac{-150}{-32} = 4.6875$

t = 4.6875 is axis of symmetry line

(e) x-coordinate of vertex is again given by formula

$x = \frac{-b}{2a}$

so t = 4.6875

then to find y coordinate we will plug this value of t as 4.6875 in equation made in part (a)

For t =4.6875, $h = -16(4.6875)^2+150(4.6875)+100 = 451.563$

so vertex is at (4.6875, 451.563)

(f) As the firework is launched so in starting time is t=0, we cannot have time before t=0 (negative values) practically. Also we cannnot have firework going down into the ground so we cannot have h value negative physically.

6 0

3 years ago

Identify the y-intercept of the line 2x-y=6

nadya68 [22]

Answer:

-6

Step-by-step explanation:

2×-y=6

subtract the 2x

-y=-2×+6

divided by negative 1 on both sides

y=2×-6

7 0

3 years ago