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dimulka [17.4K]
3 years ago
5

What can you press to move around the calculator when making lists?

Mathematics
1 answer:
erastova [34]3 years ago
5 0

Answer:

The arrow buttons on the calculator

Step-by-step explanation:

It mostly matters on what kind of calculator have but most calculators are like that.

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Hello! Can someone help me with this, please?
Trava [24]

Answer:

5.5 ft

Hope this helped!

5 0
2 years ago
Read 2 more answers
A diver descends to a location of -50 1 over 4 meters relative to the surface of the water. He then descends another 10 1 over 2
Yanka [14]

Answer:

-60\frac{3}{4} meters.

Step-by-step explanation:

To find diver's final location relative to the surface of water we will subtract  10\frac{1}{2} from -50\frac{1}{4} because diver dives away another 10\frac{1}{2} from his previous location of -50\frac{1}{4}.

-50\frac{1}{4} -10\frac{1}{2}

Now we will convert our mixed fraction into improper fraction and then we will find a common denominator.

\frac{-201}{4} -\frac{21}{2} =\frac{-201-42}{4}

=\frac{-243}{4}

Now let us convert our answer in mixed fraction.

=\frac{-243}{4}=[tex]-60\frac{3}{4}[/tex]

Therefore, diver's final location relative to the surface of the water is -60\frac{3}{4} meters.

3 0
3 years ago
Read 2 more answers
If "-3<" x/5 < "-1" what is the value of x
Natalka [10]

Answer:

-15 < x < -5

Step-by-step explanation:

-3 < x/5  < -1

Multiply all sides by 5

-3*5 < x/5 *5  < -1*5

-15 < x < -5

7 0
3 years ago
Pls if anyone knows the answer with work included/steps that will be greatly appreciated :)
dimaraw [331]

Answer:

1. Option D. 15x²

2. Option C. 3

Step-by-step explanation:

1. Determination of the area of one section.

Length (L) of one section = 25x/5 = 5x

Width (W) of one section = 3x

Area (A) of one section =?

The area of one section can be obtained as follow:

Area (A) = Length (L) × Width (W)

A = L × W

A = 5x * 3x

A = 15x²

Thus, the area of one section is 15x²

2. Determination of the expressions that are equivalent to (p²)³.

We'll begin by simplifying (p²)³. This can be obtained as follow:

(p²)³ = p²*³

(p²)³ = p⁶

Next we shall compare each expression given in the question above to see which will be the same as p⁶.

p × p × p × p × p × p = p¹⁺¹⁺¹⁺¹⁺¹⁺¹

p × p × p × p × p × p = p⁶

p² × p² × p² = p²⁺²⁺²

p² × p² × p² = p⁶

p² × p³ = p²⁺³

p² × p³ = p⁵

Thus,

p² × p³ ≠ p⁶

p⁵ ≠ p⁶

p⁶ = p⁶

SUMMARY

p × p × p × p × p × p = p⁶ = (p²)³

p² × p² × p² = p⁶ = (p²)³

p⁶ = (p²)³

Therefore, 3 expressions are equivalent to (p²)³. Option C gives the correct answer to the question.

6 0
2 years ago
If no vertical line intersects the graph of a relation in more than one point, then the relation is a function.
eimsori [14]
The answer is 100% A - True.
6 0
3 years ago
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