The environmental and energy problem Kenya faces as far computer installations are concerned can be avoided by
- Knowing and finding out the key aspect of ICT strength.
- Create an holistic judgements in the assessment of ICT capability. Promote the use of solar power.
<h3>How can we overcome ICT challenges?</h3>
There are a lot of Energy Challenges in terms of ICT in Kenyan and it is good the government and the people work towards energy in terms of sustainable ICT.
Therefore, The environmental and energy problem Kenya faces as far computer installations are concerned can be avoided by
- Knowing and finding out the key aspect of ICT strength.
- Create an holistic judgements in the assessment of ICT capability. Promote the use of solar power.
Learn more about computer installations from
brainly.com/question/11430725
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Answer:
Around seven billion people
Answer:
An IDE normally consists of a source e editor, build automation tools. Most modern IDEs have intelligent code completion. Some IDEs contain a compiler, interpreter, or both.
Answer:
Explanation:
C++ Code
#include <iostream>
#include <cstdlib>
using namespace std;
int main(){
double hour,minute;
cout<<"Enter Hours :";
cin>>hour;
cout<<"Enter Minutes :";
cin>>minute;
minute = minute+15;
if(minute >=60){
hour++;
minute = minute-60;
}
if(hour>23){
hour = 0;
}
cout<<"Hour: "<< hour<< " Minutes: "<<minute;
return 0;
}
Code Explanation
First take hours and minutes as input. Then add 15 into minutes.
If minutes exceeds from 60 then increment into hours and also remove 60 from minutes as hours already incremented.
Then check if hours are greater then 23 then it means new day is start and it should be 0.
Output
Enter Hours :9
Enter Minutes :46
Hour: 10 Minutes: 1
Answer:
See Explanation
Explanation:
The question is incomplete as there is no link pointing to the houseType struct of chapter 1.
So, I've answered the question from scratch
See attachment for explanation where I used comments to explain each line.
The program is as follows:
#include <iostream>
using namespace std;
struct houseType{
int firstHouse, secondHouse;
};
int main()
{
houseType hT;
cout << "Enter the price of both house: ";
cin>> hT.firstHouse;
cin>> hT.secondHouse;
if(hT.firstHouse == hT.secondHouse){ cout<<"true"; }
else{ cout<<"false"; }
return 0;
}