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djyliett [7]
3 years ago
10

The density of copper is 8.92 g/cm3. What is the volume in L of a 230.14 mg sample of copper?

Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
8 0
D=M/V so you plug in 8.92 for the density and 230.14 for the mass. then solve and get 25.8. you may need to do dimensional analysis with the different units of measures
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Draw and label the parts of a helium atom. Include the mass and charge of each subatomic particle.
mihalych1998 [28]

Explanation:

Helium is the second element on the periodic table.

  Information about helium:

  • it belongs to group O on the periodic table
  • it is has an atomic number of 2
  • Helium exists naturally as gas and it is nonreactive.

  To write an atom we use this format:

                                     ₙᵇGˣ

   G is the symbol of the atom

   n is the atomic number  

   b is the mass number

    x is the charge on the atom

Using the periodic table as guide

    Symbol of helium is He

     Atomic number of helium is 2

     mass number of helium is 4

     charge on helium atom is 0

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Every atom contains protons, neutrons and electrons;

   Electrons are negatively charged. For a neutral atom, the number of electrons is the same as that of protons.

   Protons are positively charge particles in an atom. The atomic number is the number of protons in an atom.

   neutrons do not have charges.

 

   Helium has:

        Number of protons = 2

        Number of electrons = 2

        Number of neutrons = 2

Mass of each subatomic particle:

      1 electron = 9.11 x 10⁻³¹kg

      2 electrons = 1.82 x 10⁻³⁰kg  

     Protons and neutrons have the same mass:

           1 proton = 1.67 x 10⁻²⁷kg

           2 protons = 3.34 x 10⁻²⁷kg

           2 neutrons = 3.34 x 10⁻²⁷kg

Learn more:

helium brainly.com/question/2439349

#learnwithBrainly

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b.

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The iron(III) ions and chloride ions remain aqueous and are spectator ions in a reaction that produces solid barium sulfate.

7 0
3 years ago
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gizmo_the_mogwai [7]
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What volume of concentrated (10.2 M) HCl would be required to prepare 1.11 x 104 mL of 1.5 M HC1? Enter your answer in scientifi
Tomtit [17]

Answer:

The required volume is 1.6 x 10³mL.

Explanation:

When we want to prepare a dilute solution from a concentrated one, we can use the dilution rule to find out the required volume to dilute. This rule states:

C₁ . V₁ = C₂ . V₂

where,

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In this case, we want to find out V₁:

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