Answer:HNO3 + NaOH → H2O + NaNO3
Explanation:
Answer:
Silver and copper
Explanation:
Siliver
Electrical conductivity=62000000(s/m)
Boiling point=2162
Melting point=961.78
Phase=solid
Copper
Electrical conductivity=59000000(s/m)
Boiling point =2927
Melting point=1084.62
Phase=soild
Metals like gold, silver and copper are drawn into thin wire and are used in an electric circuit because of their high electrical conductivity
Mostly Siliver and copper are used since using gold is much expensive.
<u>Answer:</u> The amount of energy released per gram of
is -71.92 kJ
<u>Explanation:</u>
For the given chemical reaction:

The equation used to calculate enthalpy change is of a reaction is:
![\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f_{(product)}]-\sum [n\times \Delta H^o_f_{(reactant)}]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28product%29%7D%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28reactant%29%7D%5D)
The equation for the enthalpy change of the above reaction is:
![\Delta H^o_{rxn}=[(5\times \Delta H^o_f_{(B_2O_3(s))})+(9\times \Delta H^o_f_{(H_2O(l))})]-[(2\times \Delta H^o_f_{(B_5H_9(l))})+(12\times \Delta H^o_f_{(O_2(g))})]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%285%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28B_2O_3%28s%29%29%7D%29%2B%289%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28H_2O%28l%29%29%7D%29%5D-%5B%282%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28B_5H_9%28l%29%29%7D%29%2B%2812%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28O_2%28g%29%29%7D%29%5D)
Taking the standard enthalpy of formation:

Putting values in above equation, we get:
![\Delta H^o_{rxn}=[(5\times (1271.94))+(9\times (-285.83))]-[(2\times (73.2))+(12\times (0))]\\\\\Delta H^o_{rxn}=-9078.57kJ](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%285%5Ctimes%20%281271.94%29%29%2B%289%5Ctimes%20%28-285.83%29%29%5D-%5B%282%5Ctimes%20%2873.2%29%29%2B%2812%5Ctimes%20%280%29%29%5D%5C%5C%5C%5C%5CDelta%20H%5Eo_%7Brxn%7D%3D-9078.57kJ)
We know that:
Molar mass of pentaborane -9 = 63.12 g/mol
By Stoichiometry of the reaction:
If 2 moles of
produces -9078.57 kJ of energy.
Or,
If
of
produces -9078.57 kJ of energy
Then, 1 gram of
will produce =
of energy.
Hence, the amount of energy released per gram of
is -71.92 kJ
D. There must be oxygen added. 2 of them don't even have oxygen anywhere in the formula, and the 3rd loses oxygen, which is reduction.
The equilibrium constant (K) : 11.85
<h3>Further explanation</h3>
Given
Reaction
N₂(g) + 3H₂(g) ⇒ 2NH₃(g)
Required
K(equilibrium constant)
Solution
The equilibrium constant (K) is the value of the concentration product in the equilibrium
The equilibrium constant based on concentration (K) in a reaction
pA + qB -----> mC + nD
![\tt K=\dfrac{[C]^m[D]^n}{[A]^p[B]^q}](https://tex.z-dn.net/?f=%5Ctt%20K%3D%5Cdfrac%7B%5BC%5D%5Em%5BD%5D%5En%7D%7B%5BA%5D%5Ep%5BB%5D%5Eq%7D)
For the reaction above :
![\tt K=\dfrac{[NH_3]^2}{[N_2][H_2]^3}\\\\K=\dfrac{0.1^2}{0.25\times 0.15^3}\\\\K=11.85](https://tex.z-dn.net/?f=%5Ctt%20K%3D%5Cdfrac%7B%5BNH_3%5D%5E2%7D%7B%5BN_2%5D%5BH_2%5D%5E3%7D%5C%5C%5C%5CK%3D%5Cdfrac%7B0.1%5E2%7D%7B0.25%5Ctimes%200.15%5E3%7D%5C%5C%5C%5CK%3D11.85)