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2 years ago

What is the best safety practice recommended before leaving the chemistry laboratory?

Chemistry

1 answer:

alexgriva [62]2 years ago

6 0

Answer:

Washing your hands properly.

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PLEASE HELP ASAP ONLY HAVE 10 MINUTES. A certain photon of light has a wavelength of 422 x 10 -9 m. What is the frequency of the

Sedaia [141]

Answer:

7.11 x $10^{14}$ Hz

Explanation:

The equation for converting wavelength to frequency is ν=c/λ, or the speed of light over wavelength. The speed of light is 3.00 x $10^{8}$ , and our wavelength here is 422 x $10^{-9}$ . All we have to do now is substitute our given values:

$\frac{3.00x10^{8} }{422x10^{-9}}$

After reduction, our answer comes out to be about 7.11 x $10^{14}$ Hz.

4 0

2 years ago

The dog will eat more food to store fat and grow more hair.

makvit [3.9K]

hibernation exclamation mark

5 0

2 years ago

Match the characteristics of each of the substance to their category

hjlf

Answer:

Metal: C, F, G,

Nonmetal: B, E,

Metalloid: A, D, H

Explanation:

6 0

2 years ago

A balloon containing 0.0400 mol of a gas with a volume of 500 mL was expanded to 1.00 L. Answer the questions and round answers

grandymaker [24]

the number of moles 0.08

8 0

2 years ago

3. A 31.2-g piece of silver (s = 0.237 J/(g · °C)), initially at 277.2°C, is added to 185.8 g of a liquid, initially at 24.4°C,

VARVARA [1.3K]

Answer:

$Cp_{liquid}=2.54\frac{J}{g\°C}$

Explanation:

Hello,

In this case, since silver is initially hot as it cools down, the heat it loses is gained by the liquid, which can be thermodynamically represented by:

$Q_{Ag}=-Q_{liquid}$

That in terms of the heat capacities, masses and temperature changes turns out:

$m_{Ag}Cp_{Ag}(T_2-T_{Ag})=-m_{liquid}Cp_{liquid}(T_2-T_{liquid})$

Since no phase change is happening. Thus, solving for the heat capacity of the liquid we obtain:

$Cp_{liquid}=\frac{m_{Ag}Cp_{Ag}(T_2-T_{Ag})}{-m_{liquid}(T_2-T_{liquid})} \\\\Cp_{liquid}=\frac{31.2g*0.237\frac{J}{g\°C}*(28.3-227.2)\°C}{185.8g*(28.3-24.4)\°C}\\ \\Cp_{liquid}=2.54\frac{J}{g\°C}$

Best regards.

6 0

3 years ago