<u>Answer:</u> The mass of excess reagent (ammonium chloride) remained after the reaction is 62.7 grams
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
- <u>For aluminium nitrite:</u>
Given mass of aluminium nitrite = 27.4 g
Molar mass of aluminium nitrite = 41 g/mol
Putting values in equation 1, we get:
![\text{Moles of aluminium nitrite}=\frac{27.4g}{41g/mol}=0.668mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20aluminium%20nitrite%7D%3D%5Cfrac%7B27.4g%7D%7B41g%2Fmol%7D%3D0.668mol)
- <u>For ammonium chloride:</u>
Given mass of ammonium chloride = 169.9 g
Molar mass of ammonium chloride = 53.5 g/mol
Putting values in equation 1, we get:
![\text{Moles of ammonium chloride}=\frac{169.9g}{53.5g/mol}=3.176mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20ammonium%20chloride%7D%3D%5Cfrac%7B169.9g%7D%7B53.5g%2Fmol%7D%3D3.176mol)
The chemical equation for the reaction of aluminium nitrite and ammonium chloride follows:
![Al(NO_2)_3+3NH_4Cl\rightarrow AlCl_3+3N_2+6H_2O](https://tex.z-dn.net/?f=Al%28NO_2%29_3%2B3NH_4Cl%5Crightarrow%20AlCl_3%2B3N_2%2B6H_2O)
By Stoichiometry of the reaction:
1 mole of aluminium nitrite reacts with 3 moles of ammonium chloride
So, 0.668 moles of aluminium nitrite will react with =
of ammonium chloride.
As, given amount of ammonium chloride is more than the required amount. So, it is considered as an excess reagent.
Thus, aluminium nitrite is considered as a limiting reagent because it limits the formation of product.
Excess moles of ammonium chloride = (3.176 - 2.004) mol = 1.172 moles
Calculating the mass of ammonium chloride by using equation 1, we get:
Excess moles of ammonium chloride = 1.172 moles
Molar mass of ammonium chloride = 53.5 g/mol
Putting values in equation 1, we get:
![1.172mol=\frac{\text{Mass of ammonium chloride}}{53.5g/mol}\\\\\text{Mass of ammonium chloride}=(1.172mol\times 53.5g/mol)=62.7g](https://tex.z-dn.net/?f=1.172mol%3D%5Cfrac%7B%5Ctext%7BMass%20of%20ammonium%20chloride%7D%7D%7B53.5g%2Fmol%7D%5C%5C%5C%5C%5Ctext%7BMass%20of%20ammonium%20chloride%7D%3D%281.172mol%5Ctimes%2053.5g%2Fmol%29%3D62.7g)
Hence, the mass of excess reagent (ammonium chloride) remained after the reaction is 62.7 grams