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Nostrana [21]
3 years ago
7

What does the /var directory contain?

Computers and Technology
1 answer:
Ghella [55]3 years ago
3 0

Answer:A

Explanation:

The /var Directory. /var is a standard subdirectory of the root directory in Linux and other Unix-like operating systems that contains files to which the system writes data during the course of its operation

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What is the output of the following C++ program?
KIM [24]

Answer:

Output:<em> </em><em>15 11/16 inches</em>

Explanation:

#include <iostream>

using namespace std;

////////////////////////////////////////////////////////////////////////

class InchSize {

public:

   InchSize(int wholeInches = 0, int sixteenths = 0);

   void Print() const;

   InchSize operator+(InchSize rhs);

   

private:

   int inches;

   int sixteenths;

};

InchSize InchSize::operator+(InchSize rhs) {

   InchSize totalSize;

   totalSize.inches = inches + rhs.inches;

   totalSize.sixteenths = sixteenths + rhs.sixteenths;

   

   // If sixteenths is greater than an inch, carry 1 to inches.

   if (totalSize.sixteenths >= 16) {

       totalSize.inches += 1;

       totalSize.sixteenths -= 16;

   }

   return totalSize;

}

InchSize::InchSize(int wholeInches, int sixteenthsOfInch) {

   inches = wholeInches;

   sixteenths = sixteenthsOfInch;

}

void InchSize::Print() const {

   cout<<inches<<" "<<sixteenths<<"/16 inches"<<endl;

}

////////////////////////////////////////////////////////////////////////

int main() {

   InchSize size1(5, 13);

   InchSize size2(9, 14);

   InchSize sumSize;

   sumSize = size1 + size2;

   sumSize.Print();

   return 0;

}

////////////////////////////////////////////////////////////////////////

sumSize variable was printed in the end. Print() prints the calling object's inches and sixteenths variables' values.

sumSize's inches is equal to size1 plus size2's inches.

Because the sum of sixteenths was greater than 16, sumSize's sixteenth was decreased by 1 and inches was increased by 1.

3 0
3 years ago
A network administrator is configuring an ACL with the command access-list 10 permit 172.16.32.0 0.0.15.255. Which IPv4 address
lord [1]

Answer:

For this wild card mask 0.0.15.255 the ACE IP address will be 172.16.47.254

Explanation:

ACL is the access control list that is used to enlist the ip addresses that allowed or restricted to access the network. ACE is an IP address from the list ACL that has all rules and regulations related to access of network. The ACE could be in the range of IP address in ACL. ACL can be calculated with the help of initial IP address adding with wild card mask.

So

Initial IP address is = 172.16.32.0

Wild card mask =0.0.15.255

by adding above values we can find the last IP address of ACL.

after addition

Final IP address is = 172.16.47.255

The options that are available with question, Only option between the range is  172.16.47.254. So we can say that This is the only ACE IP address in options.

7 0
3 years ago
You have just taken over management of a server on which the previous server administrator has set up several server components,
Arisa [49]

Answer:

d. Ensure file caching and flushing are enabled for all disk drives.

Explanation:

When the disk reading and writing is delayed and the server performance is also slow after taking over management of a server.Previously the server has several server components.So to increase the performance we should ensure caching of the file and make sure that the flushing is enabled for all disk drives.Hence the answer to this question is option d.

8 0
2 years ago
Write 'T' for true and 'F' for false statements.
asambeis [7]
1-F
2-T
3-F
4-F
5-F
6 T
7-T
3 0
2 years ago
HELP WILL MARK BRAINLIEST!!!!!!!!!!!!!!!!!<br> How do you take a screenshot on Windows 7?
Alina [70]
U can see the printscr botton at the top right of ur keyboard and then u can type paint and the control v. 
3 0
3 years ago
Read 2 more answers
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