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gulaghasi [49]
4 years ago
11

If z=3−5i, find |z|.

Mathematics
1 answer:
geniusboy [140]4 years ago
5 0

Answer:

Step-by-step explanation:

The absolute value of z is the distance between the point graphed from the complex number and the origin on a complex plane.  In a complex plane, the x axis is replaced by R, real numbers, and the y axis is replaced by i, the complex part of the complex number.  Our real number is positive 3 and the complex number is -5, so we go to the right 3 and then down 5 and make a point.  Connect that point to the origin and then connect the point to the x axis at 3 to construct a right triangle that has a base of 3 and a length of -5.  To find the distance of the point to the origin is to find the length of the hypotenuse of that right triangle using Pythagorean's Theorem.  Therefore:

|z|=\sqrt{(3)^2+(-5)^2} and

|z|=\sqrt{9+25} and

|z|=\sqrt{34}

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Which triangles could not be similar to triangle ABC ? triangle a b c where angle b is a right angle. side a b is 15 cm. side b
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Answer:

option (b) and (d) are correct.

 Right triangle J K L with right angle at K. J K is 60 centimeters. J L is 68 centimeters. K L is 32 centimeters.

and Right triangle D E F with right angle at E. D E is 22.5 centimeters. D F is 25.5 centimeters. E F is 12 centimeters.

Step-by-step explanation:

Given : triangle a b c where angle b is a right angle. side a b is 15 cm. side b c is 8 cm. side a c is 17 cm.

We have to select triangle from given options that are similar to ΔABC,

Two triangles are said to be  similar when their corresponding sides are in same ratios  and their corresponding angles are equal.

Consider : Right triangle J K L with right angle at K. J K is 60 centimeters. J L is 68 centimeters. K L is 32 centimeters.

FINDING CORRESPONDING RATIOS,

\frac{AB}{JK}=\frac{15}{60}=\frac{1}{4}

\frac{BC}{KL}=\frac{8}{32}=\frac{1}{4}

\frac{AC}{JL}=\frac{17}{68}=\frac{1}{4}

Since, ratios are equal. Thus, triangles are similar.

ΔABC ≅ ΔJKL

Consider : Right triangle D E F with right angle at E. D E is 22.5 centimeters. D F is 25.5 centimeters. E F is 12 centimeters.

FINDING CORRESPONDING RATIOS,

\frac{AB}{DE}=\frac{15}{22.5}=\frac{2}{3}

\frac{BC}{EF}=\frac{8}{12}=\frac{2}{3}

\frac{AC}{DF}=\frac{17}{25.5}=\frac{2}{3}

Since, ratios are equal. Thus, triangles are similar.

ΔABC ≅ ΔDEF

Thus, option (b) and (d) are correct.


3 0
4 years ago
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