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Harlamova29_29 [7]
3 years ago
9

What is the decimal of 32/100​

Mathematics
1 answer:
katen-ka-za [31]3 years ago
7 0

Answer:

0.32

Step-by-step explanation:

Simply divide 32 into 100 and get 0.32

you could put it into a calculator or write it out and divide.

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Mr. Wang is buying a $15 box of trail mix at Whole Foods, where tax is 6%. If Mr. Wang has a coupon for 10% off the price of any
algol13

Answer:

$47 plus whole foods market

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What are the steps to solve √(0.2)^(−2)?<br><br>(The answer is 5)
Nimfa-mama [501]

\bf 0.\underline{2}\implies \cfrac{02}{1\underline{0}}\implies \stackrel{simplified}{\cfrac{1}{5}} \\\\[-0.35em] ~\dotfill\\\\ \left( \sqrt{0.2} \right)^{-2}\implies \left( \sqrt{\cfrac{1}{5}}\right)^{-2}\implies \left( \sqrt{\cfrac{5}{1}}\right)^{+2}\implies \cfrac{(\sqrt{5})^2}{(\sqrt{1})^2}\implies \cfrac{\sqrt{5^2}}{\sqrt{1^2}}\implies 5

6 0
3 years ago
∠EFG and ∠LMN are supplementary angles, m∠EFG=(3x+17)º, and m∠LMN=(12x−5)º.
Ira Lisetskai [31]

Answer:

EFG = 50.6, LMN = 129.4

Step-by-step explanation:

ok so s supplementary angles mean, their angles will always add upto 180. for example if one angle is 100° then the other will be 80°.

to find the angles first we need to solve for x.

we know EFG + LMN = 180 because its supplementary.

that's is (3x+17) + (12x-5) = 180.

we now solve for x;

15x+12 = 180

15x = 168, x= 168/15 = 11.2

now that we know x we can put this value in the corresponding equation of EFG and LMN to find the angles.

EFG = 3x11.2 + 17 = 50.6

LMN = 12x11.2 - 5 = 129.4

7 0
3 years ago
6x - 2y = 5
laiz [17]

Answer:

The given system has NO SOLUTION.

Step-by-step explanation:

Here, the given system of equation is:

6 x -  2 y = 5     .......... (1)

3 x  - y = 10          .... (2)

Multiply equation 2 with (-2), we get:

3 x  - y = 10     ( x -2)

⇒  - 6 x + 2 y = - 20

Now, ADD this to equation (1) , we get:

6 x - 2 y  - 6 x + 2 y  = 5 - 20

or, 0 = - 15

WHICH IS NOT POSSIBLE as 0 ≠ -15

Hence, the given system has NO SOLUTION.

7 0
3 years ago
Use the Trapezoidal Rule, the Midpoint Rule, and Simpson's Rule to approximate the given integral with the specified value of n.
Vera_Pavlovna [14]

Split up the integration interval into 4 subintervals:

\left[0,\dfrac\pi8\right],\left[\dfrac\pi8,\dfrac\pi4\right],\left[\dfrac\pi4,\dfrac{3\pi}8\right],\left[\dfrac{3\pi}8,\dfrac\pi2\right]

The left and right endpoints of the i-th subinterval, respectively, are

\ell_i=\dfrac{i-1}4\left(\dfrac\pi2-0\right)=\dfrac{(i-1)\pi}8

r_i=\dfrac i4\left(\dfrac\pi2-0\right)=\dfrac{i\pi}8

for 1\le i\le4, and the respective midpoints are

m_i=\dfrac{\ell_i+r_i}2=\dfrac{(2i-1)\pi}8

  • Trapezoidal rule

We approximate the (signed) area under the curve over each subinterval by

T_i=\dfrac{f(\ell_i)+f(r_i)}2(\ell_i-r_i)

so that

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4T_i\approx\boxed{3.038078}

  • Midpoint rule

We approximate the area for each subinterval by

M_i=f(m_i)(\ell_i-r_i)

so that

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4M_i\approx\boxed{2.981137}

  • Simpson's rule

We first interpolate the integrand over each subinterval by a quadratic polynomial p_i(x), where

p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}

so that

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx

It so happens that the integral of p_i(x) reduces nicely to the form you're probably more familiar with,

S_i=\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{r_i-\ell_i}6(f(\ell_i)+4f(m_i)+f(r_i))

Then the integral is approximately

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4S_i\approx\boxed{3.000117}

Compare these to the actual value of the integral, 3. I've included plots of the approximations below.

3 0
3 years ago
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