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GarryVolchara [31]
3 years ago
14

Please solve for the inverse variation equation

Mathematics
1 answer:
mojhsa [17]3 years ago
8 0

Answer:

f(x) = \frac{1}{x-2} + 1

Step-by-step explanation:

First we identify the Vertical Asymptote. Which is at x = 2

The function has a VA only at the point where the denominator gives 0, so because we know x = 2 is the VA, the denominator will be x - 2.

Then we identify the Horizontal Asymptote, which is the behavior of the function for very large 'x', or the horizontal line of the graph on the y - axis. Which is at y = 1. So our function will go to 1, as x grows incredibly large.

But since our denominator is x - 2, the top remains 1, but we should add a 1 to the function so it really has a HA at y = 1.

f(x) = \frac{1}{x-2} + 1

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\boldsymbol{\mathbf{1235520\,different\, ways\,can\,six\, people\,be\, selected}}

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The flight of a cannonball toward a hill is described by the parabola y=2+0.12x- 0.0004x^2
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The computation shows that the placw on the hill where the cannonball land is 3.75m.

<h3>How to illustrate the information?</h3>

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The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?

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