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Eddi Din [679]
3 years ago
10

Y=4x^2+x-1 solve using quadratic formula

Mathematics
1 answer:
melamori03 [73]3 years ago
7 0

Answer:

x = sqrt(17)/8 - 1/8 or x = -1/8 - sqrt(17)/8

Step-by-step explanation using the quadratic formula:

Solve for x over the real numbers:

4 x^2 + x - 1 = 0

Divide both sides by 4:

x^2 + x/4 - 1/4 = 0

Add 1/4 to both sides:

x^2 + x/4 = 1/4

Add 1/64 to both sides:

x^2 + x/4 + 1/64 = 17/64

Write the left hand side as a square:

(x + 1/8)^2 = 17/64

Take the square root of both sides:

x + 1/8 = sqrt(17)/8 or x + 1/8 = -sqrt(17)/8

Subtract 1/8 from both sides:

x = sqrt(17)/8 - 1/8 or x + 1/8 = -sqrt(17)/8

Subtract 1/8 from both sides:

Answer: x = sqrt(17)/8 - 1/8 or x = -1/8 - sqrt(17)/8

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Recall that

sin(<em>a</em> + <em>b</em>) = sin(<em>a</em>) cos(<em>b</em>) + cos(<em>a</em>) sin(<em>b</em>)

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To get 14 cos(39<em>x</em>) sin(19<em>x</em>) on the right side, multiply both sides by 7 and replace <em>a</em> = 19<em>x</em> and <em>b</em> = 39<em>x</em> :

7 (sin(19<em>x</em> + 39<em>x</em>) + sin(19<em>x</em> - 39<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

7 (sin(58<em>x</em>) + sin(-20<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

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4 0
3 years ago
Are these answers correct?
Nikolay [14]

Answer:

You're correct.

Step-by-step explanation:

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2 years ago
What are the coordinates of the image of C if it is reflected across the x-axis?
Svetradugi [14.3K]

Answer:

(-2, 4)

Step-by-step explanation:

~When reflecting a point of the x-axis, the x value (or first number inside the parenthesis) does not change.

The reason the x-value does not change is because you are reflecting over the x-axis, making the point go up or down. That will change the y-value but the x-value only changes if you move to the left or the right. In this case, you can see that the point's x-value is -2, so that will not change. It's current y-value however is -4. When reflecting over an axis, the number that is changing (in this case the y-value) will just be flipped from positive to negative, or vise versa. In this case, -4 will be reflected to be 4, making point C reflected over the x-axis (-2, 4).

5 0
3 years ago
Read 2 more answers
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