Question

Help with this algebra question

Answer 1

We have:
 3x + 4y = 12
 The first thing we should do in this case is clear and.
 We have then:
 4y = -3x + 12
 y = (- 3x + 12) / (4)
 Rewriting:
 y = (- 3/4) x + 3
 We evaluate now for x = 4
 y = (- 3/4) (4) + 3
 y = -3 + 3
 y = 0
 The ordered pair is:
 (x, y) = (4, 0)
 Answer:
 y = (- 3/4) x + 3
 (x, y) = (4, 0)

Answer 2

We have that
3x+4y=12
for x=4
3*4+4y=12-----------> y=0

pair is (4,0)