Answer:
The interquartile range is 10.
Step-by-step explanation:
(xu-xl)=10
There could be five in each class.
We need Pythagoras theorem here
a^2+b^2 = c^2
a, b = legs of a right-triangle
c = length of hypotenuse
Let S=shorter leg, in cm, then longer leg=S+2 cm
use Pythagoras theorem
S^2+(S+2)^2 = (10 cm)^2
expand (S+2)^2
S^2 + S^2+4S+4 = 100 cm^2 [collect terms and isolate]
2S^2+4S = 100-4 = 96 cm^2
simplify and form standard form of quadratic
S^2+2S-48=0
Solve by factoring
(S+8)(S-6) = 0 means (S+8)=0, S=-8
or (S-6)=0, S=6
Reject nengative root, so
Shorter leg = 6 cm
Longer leg = 6+2 cm = 8 cm
Hypotenuse (given) = 10 cm
Answer:
see explanation
Step-by-step explanation:
Using the Addition formula for sine
sin(x ± y) = sinxcosy ± cosxsiny
Consider the left side
sin(360 - Θ ), then
= sin360°cosΘ - cos360°sinΘ
= 0 × cosΘ - 1 × sinΘ
= 0 - sinΘ = - sinΘ → verified
