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4 years ago

Which would the phrase five times the sum of a number and 6 look like as a variable expression

Mathematics

2 answers:

Arada [10]4 years ago

8 0

5(x+6) is the answer.

Hope this helps!

il63 [147K]4 years ago

6 0

5 times (number + 6) so the answer would be

5(x+6). Hope this helps!

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Free piont (so this will not get delete) 7x8x3=

SVEN [57.7K]

Answer:

168

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Which ordered pairs is a solution to −5x + 3y > 12?

In-s [12.5K]

Answer :-

Given inequality ,

-5x +3y > 12
3y > 5x + 12
y > 5/3x + 12/3
y > 5/3x + 4

From the options ,

When x is 3 and y = 9

y >1* 5 + 4
y > 5 +4
9> 9 ( Not possible )

When x is -5 y is 5

y > 5/3*-5 + 4
y > -8.3 + 4
5 > -3.7 ( Possible )

When x is 3 y is -6

y > 5 + 4
-6 > 9 ( Not possible )

When x is -2 y is -5

y > -3.33 + 4
-5 > -0.67 ( Possible )

When x is 2 y is 8

y > 3.33 + 4
8 > 7.77 ( possible )

When x is -6 y is 0

y > -10 +4
0 > -6 ( possible )

7 0

3 years ago

Read 2 more answers

Nikolai has a jar filled with 120 marbles. he has 72 red marbles, 17 blue marbles, 13 green marbles, and 18 purple marbles. what

asambeis [7]

To find the probability of both of these occurring, you will multiply the probability of choosing a blue marble by the probability of choosing a purple marble (with no replacement after the first one).

Probability of choosing a blue marble: 17/120
Probability of choosing a purple marble: 18/119

17/120 x 18/119 = 3/140

You will have a 3/140 chance of both of these occurring.

4 0

3 years ago

PLEASE SOMEONE HELP ME

mylen [45]

Answer:

Step-by-step explanation:

4 0

3 years ago

This is Matrix for pre calc

gavmur [86]

The given system of equations in augmented matrix form is

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\-6&1&2&4&-12\\1&-3&-3&5&-20\\-2&5&6&0&12\end{array}\right]$

If you need to solve this, first get the matrix in RREF:

Add 2(row 1) to row 2, row 1 to -3(row 3), and 2(row 1) to 3(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&11&5&-13&37\\0&19&10&4&-10\end{array}\right]$

Add 11(row 2) to -5(row 3), and 19(row 1) to -5(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&-164&132&-1052\end{array}\right]$

Add 164(row 3) to -91(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&13080&-39240\end{array}\right]$

Multiply row 4 by 1/13080:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&1&-3\end{array}\right]$

Add -153(row 4) to row 3:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&0&-364\\0&0&0&1&-3\end{array}\right]$

Multiply row 3 by -1/91:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add 6(row 3) and -8(row 4) to row 2:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&0&0&-10\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 2 by 1/5:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add -2(row 2), 4(row 3), and -2(row 4) to row 1:

$\left[\begin{array}{cccc|c}3&0&0&0&3\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 1 by 1/3:

$\left[\begin{array}{cccc|c}1&0&0&0&1\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

So the solution to this system is $(w,x,y,z)=(1,-2,4,-3)$ .

6 0

4 years ago