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seropon [69]
3 years ago
5

The answer please anybody I need to get a A

Mathematics
2 answers:
Alborosie3 years ago
7 0

Answer:

Infinity

Step-by-step explanation:

Because there are lots of ways

ozzi3 years ago
7 0

Infinity because their is lots of side

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12/21 in its simplest form
UNO [17]
12/21 in its simplest form is 4/7.

To find this out we need to divide the numerator and denominator by the GCF of 12 and 21 which is 3.

12/21

12 ÷ 3 = 4
21 ÷ 3 = 7
4/7

12/21 in its simplest form is 4/7.

12/21 = 4/7
5 0
3 years ago
Read 2 more answers
The circumference of a circle is 15 centimeters. What is the diameter? Round to the nearest hundredths place.
lesya692 [45]

Answer:

4.77

Step-by-step explanation:

because Circumference can be found with this equation

C = 2piR

we need to plug in 15 for Circumference and solve for its radius or R.

15 = 2piR

15/2pi = R

but we need diameter which is 2R so we just need to multiply the answer by 2.

15/2pi × 2 = Diameter

15/pi = D

approximately = 4.77

6 0
3 years ago
Which of the following equations would not be a line when graphed? Explain how you can tell by just looking at the equations.
zlopas [31]
Y=2/x. this equation has degree -1 whereas linear functions have degree 1

y=6x²-7 is nonlinear as it is degree 2
5 0
3 years ago
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Find four numbers that form a geometric progression such that the third term is greater than the first by 12 and the fourth is g
olchik [2.2K]

If x is the first number in the progression, and r is the common ratio between consecutive terms, then the first four terms in the progression are

\{x,xr,xr^2,xr^3\}

We want to have

\begin{cases}xr^2-x=12\\xr^3-xr=36\end{cases}

In the second equation, we have

xr^3-xr=xr(r^2-1)=36

and in the first, we have

xr^2-x=x(r^2-1)=12

Substituting this into the second equation, we find

xr(r^2-1)=12r=36\implies r=3

So now we have

\begin{cases}9x-x=12\\27x-3x=36\end{cases}\implies x=\dfrac32

Then the four numbers are

\left\{\dfrac32,\dfrac92,\dfrac{27}2,\dfrac{81}2\right\}

4 0
3 years ago
The area of the vegetable garden is 0.4 of the community area of 4.5 x 6.2 . What is the area of the vegetable garden?
Gala2k [10]

Answer:

11.16 units²

Step-by-step explanation:

Area of community area=4.5×6.2= 27.9 units²

Area of vegetable garden=27.9×0.4=11.16 units²

5 0
3 years ago
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