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Serjik [45]
3 years ago
6

What is the greatest common factor of 63b^2c^4 and 42b^3c^2

Mathematics
2 answers:
Arte-miy333 [17]3 years ago
6 0

Factor out the GCF of  

21

b

2

c

2

from  

63

b

2

c

4

+

42

b

3

c

2

.

Tap for fewer steps...

Factor out the GCF of  

21

b

2

c

2

from each term in the polynomial.

Tap for fewer steps...

Factor out the GCF of  

21

b

2

c

2

from the expression  

63

b

2

c

4

.

21

b

2

c

2

(

3

c

2

)

+

42

b

3

c

2

Factor out the GCF of  

21

b

2

c

2

from the expression  

42

b

3

c

2

.

21

b

2

c

2

(

3

c

2

)

+

21

b

2

c

2

(

2

b

)

Since all the terms share a common factor of  

21

b

2

c

2

, it can be factored out of each term.

21

b

2

c

2

(

3

c

2

+

2

b

)

The greatest common factor  

GCF

is the term in front of the factored expression.

21

b

2

c

2

Oksana_A [137]3 years ago
3 0

Answer:

21b^2c^2

Step-by-step explanation:idk to be honest lol

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iogann1982 [59]
h(x)=(f\circ g)(x)
\sqrt{x+5}=\sqrt{g(x)+2}
x+5=g(x)+2
g(x)=x+3

Just to check this is correct:

(f\circ g)(x)=f(g(x))=f(x+3)=\sqrt{(x+3)+2}=\sqrt{x+5}=h(x)
6 0
3 years ago
A customer at a Mexican diner placed an order for 3 burrito bowls which was priced at $x each. He also ordered a plate of corn t
Daniel [21]

Answer:

x=$7

Step-by-step explanation:

The total cost of bill is $32, $11 is from a plate of corn tacos. And there are 3 purchased burrito bowls at a cost of $x each.

$32 (total bill)

-$11 (tacos)

=$21

$21 / 3 (burrito bowls)

=$7

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5 0
3 years ago
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Use the null hypothesis H0 : μ = 98.6, alternative hypothesis Ha: μ &lt; 98.6, and level of significance α = 0.05. 98 99.6 97.8
andrezito [222]

Answer:

The t-score is -1.8432    

Step-by-step explanation:

We are given the following in the question:  

98, 99.6, 97.8, 97.6, 98.7, 98.4, 98.9, 97.1, 99.2, 97.4, 99.1, 96.9, 98.8, 99.9, 96.8, 97, 98.7, 97.6, 98.7, 98.2

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{1964.4}{20} = 98.22

Sum of squares of differences = 16.152

s = \sqrt{\dfrac{16.152}{49}} = 0.922

Population mean, μ = 98.6

Sample mean, \bar{x} = 98.22

Sample size, n = 20

Sample standard deviation, s = 0.922

First, we design the null and the alternate hypothesis

H_{0}: \mu = 98.6\\H_A: \mu < 98.6

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{98.22 - 98.6}{\frac{0.922}{\sqrt{20}} } = -1.8432

The t-score is -1.8432    

7 0
2 years ago
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erastovalidia [21]

Step-by-step explanation:

do u want to solve it or wat do u mean

7 0
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Vikentia [17]

Answer:

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Step-by-step explanation:

=50+50×5%

=50+2.5

=52.5

3 0
3 years ago
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