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Serjik [45]
3 years ago
6

What is the greatest common factor of 63b^2c^4 and 42b^3c^2

Mathematics
2 answers:
Arte-miy333 [17]3 years ago
6 0

Factor out the GCF of  

21

b

2

c

2

from  

63

b

2

c

4

+

42

b

3

c

2

.

Tap for fewer steps...

Factor out the GCF of  

21

b

2

c

2

from each term in the polynomial.

Tap for fewer steps...

Factor out the GCF of  

21

b

2

c

2

from the expression  

63

b

2

c

4

.

21

b

2

c

2

(

3

c

2

)

+

42

b

3

c

2

Factor out the GCF of  

21

b

2

c

2

from the expression  

42

b

3

c

2

.

21

b

2

c

2

(

3

c

2

)

+

21

b

2

c

2

(

2

b

)

Since all the terms share a common factor of  

21

b

2

c

2

, it can be factored out of each term.

21

b

2

c

2

(

3

c

2

+

2

b

)

The greatest common factor  

GCF

is the term in front of the factored expression.

21

b

2

c

2

Oksana_A [137]3 years ago
3 0

Answer:

21b^2c^2

Step-by-step explanation:idk to be honest lol

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Vikki [24]
I think it's d okay maybe
8 0
3 years ago
3. The first three place values to the right of the decimal point are the tenths place, the hundredths place, and the thousandth
Katarina [22]

Answer:

True

Step-by-step explanation:

0     .      0                0                     0

whole     Tenths      Hundredths    Thousandths

3 0
3 years ago
Annie’s change purse contained 5 quarters 8 dimes and 8 nickels if Annie chose 2 coin randomly without replacing them in her pur
Bogdan [553]
<h3>Answer:</h3>

2/15

<h3>Explanation:</h3>

There are 8C2 = 28 ways to choose 2 dimes from the 8 dimes in Annie's purse. There are 21C2 = 210 ways to choose 2 coins from the 21 coins in Annie's purse.

Of the 210 ways to choose 2 coins, 28 of the choices will result in 2 dimes being chosen. The probability of choosing 2 dimes is 28/210 = 2/15.

_____

<em>Comment on nCk</em>

The number of ways to choose k objects from n, when order does not matter, is ...

... n!/(k!(n -k)!)

For the computations above, we have ...

... 8C2 = 8·7/(2·1) = 28

... 21C2 = 21·20/(2·1) = 210

8 0
3 years ago
A shipping service restricts the dimensions of the boxes it will ship for a certain type of service.
Mandarinka [93]

Answer:

Then the answer is option a  

a. 0<x \leq10

Step-by-step explanation:

perimeter + height is less than 130 inches.

If height is 60 inches.then perimeter left is 70 inches.

If perimeter was more than 70 inches then perimeter 60 more than the height would be more than 130.

perimeter of rectangle is

It has two widths and two lengths because that's what rectangles do.

width of base "x"

Then the length is 2.5x

perimeter = 2 width + 2 length

= 2(x) + 2(2.5x)

= 2x + 5x

= 7x

but perimeter can't be more than 70 inches.

So x can't be more than 10 inches because if x was more than 10 inches, then 7x which is perimeter would be more than 70 inches.

2x + 2(2.5x) + 60 \leq  130

7x + 60 ≤ 130

7x ≤ 70

x ≤ 10

Then the answer is option a  

a. 0<x≤10

3 0
3 years ago
Ok at this triangle.<br> B<br> 11 cm<br> 4 cm<br> A<br> C<br> workout length AC.
Naddik [55]

Answer:

<c =90 ° So, Pythagoras theorem can be used, Hypotenuse ² = base ² + altitude ²AB²=AC²+BC²11²=AC²+4²11²-4²=AC²121-16=AC²Root 105=ACAC=10.2 cm

Step-by-step explanation:

Mark me brainliest!!

8 0
3 years ago
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