Question

Which expression represents the approximate length of Line segment B C? Use law of sines

Answer 1

Answer:

The expression is

$BC=\frac{3}{sin(38^o)}sin(66^o)$

$BC=4.45\ units$

Step-by-step explanation:

we know that

In the triangle ABC

Applying the law of sines

$\frac{AB}{sin(C)}=\frac{BC}{sin(A)}$

we have

$AB=3\ units\\C=38^o\\A=66^o$

substitute the given values

$\frac{3}{sin(38^o)}=\frac{BC}{sin(66^o)}$

Solve for BC

$BC=\frac{3}{sin(38^o)}sin(66^o)$

$BC=4.45\ units$