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slavikrds [6]
3 years ago
12

Help me with this problem please It would make it so much easer

Mathematics
2 answers:
san4es73 [151]3 years ago
7 0
Hannah and Francine have $120. Hannah and Peter have $230. Peter has 6 times as much as much money as Francine.

Let the amount with Hannah be represented by x.

As Hannah and Francine have $120, the amount with Francine is 120 - x

As Hannah and Peter have $230, the amount with Peter is 230 - x

Now Peter has 6 times as much as much money as Francine. This gives:

230 - x = 6*(120 - x)

230 - x = 720 - 6x

5x = 490

x = 490/5

x = 98

This gives the amount with Hannah as $98
Svetllana [295]3 years ago
3 0
The answer is that Francine has $38
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Aleks04 [339]

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8 0
3 years ago
Select two choices that are true about the function f(x)=23x+14/x
WINSTONCH [101]

Answer:

There is an asymptote at x = 0

There is an asymptote at y = 23

Step-by-step explanation:

Given the function:

(23x+14)/x

Vertical asymptote is gotten by equating the denominator to zero

Since the denominator is x, hence the vertical asymptote is at x = 0. This shows that there is an asymptote at x = 0

Also for the horizontal asymptote, we will take the ratio of the coefficient of the variables in the numerator and denominator

Coefficient of  x at the numerator = 23

Coefficient of x at the denominator = 1

Ratio = 23/1 = 23

This means that there is an asymptote at y = 23

8 0
3 years ago
SOME ONE PLEASE ACTUALLY HELP ME
Pie

Answer:

y = 658.3 ft

Step-by-step explanation:

x = 745.5 ft

y = 658.3 ft

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Answered by GAUTHMATH

5 0
3 years ago
(7p+8)-(5p-2) combine like terms
kotegsom [21]
The answer is:<span>
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8 0
3 years ago
Use each model to predict the life expectancy of residents of a country for which the average annual income is $80,000
Mandarinka [93]

The life expectancies of residents of a country for which the average annual income is $80,000 for the three models are 12309.9352, 172.2436 and 4828.1393

The life expectancies of the models are given as:

y =69.9352 + 0.1530\times (income) --- model 1

y =4.2436 + 0.0021\times (income) --- model 2

y =4.1393 + 0.0603\times (income) --- model 3

Given that the average annual income is $80,000;

We simply substitute 80000 for income in the equations of the three models.

So, we have:

<u>Model 1</u>

y =69.9352 + 0.1530\times (income)

y =69.9352 + 0.1530\times 80000

y =12309.9352

<u>Model 2</u>

y =4.2436 + 0.0021\times (income)

y =4.2436 + 0.0021\times 80000

y =172.2436

<u>Model 3</u>

y =4.1393 + 0.0603\times (income)

y =4.1393 + 0.0603\times 80000

y =4828.1393

Hence, the life expectancies are 12309.9352, 172.2436 and 4828.1393

Read more about linear models at:

brainly.com/question/8609070

4 0
2 years ago
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