All categories

3 years ago

Find the measure of a central angle that intercepts an arc of 81.5 cm in a circle whose radius is 16.3 cm.

Mathematics

1 answer:

Molodets [167]3 years ago

8 0

Answer:

The awnser is 5

I think...

You might be interested in

What is the value of x?

USPshnik [31]

Answer:

x = 18

Step-by-step explanation:

b squared + x squared = 30 squared

8 0

3 years ago

Evaluate these please [-4+9]<br> [-4]+9

Andrews [41]

Answer:

-11

Step-by-step explanation:

Simplify

5×−4+9

Simplify

−20+9

Answer

−11

6 0

3 years ago

Please help how do i find the area of the shape?

Orlov [11]

Answer:

Do not listen to the other answer! Here is how you solve that.

Step-by-step explanation:

For the semicircle, here is the formula for area: $A= \frac{1}{2}(\pi r^2)$

For the triangle, here is the formula for area: $A=\frac{1}{2}(bh)$

Then, add.

So,

Triangle:

$A=\frac{1}{2}(9*12)$

$A=54$

Semicircle:

$A=\frac{1}{2}(\pi 6^2)$

$A=18\pi$

Your answer is $Area = 54 + 18\pi$

6 0

3 years ago

Please Answer??? The binomial expansion of (2x-y)^3 is

Marina86 [1]

Your answer is B.

I hope this helped :-)

Could I have brainly-ist?

3 0

3 years ago

Read 2 more answers

given that 8-sqrt(18) over sqrt(2) = a + b sqrt(2) where a and b are integers find the value of a and b

Novay_Z [31]

Answer:

a = - 3 and b = 4

Step-by-step explanation:

Given

$\frac{8-\sqrt{18} }{\sqrt{2} }$

Simplify $\sqrt{18}$

= $\sqrt{9(2)}$ = $\sqrt{9}$ × $\sqrt{2}$ = 3 $\sqrt{2}$

Thus expression can be written as

$\frac{8-3\sqrt{2} }{\sqrt{2} }$

Multiply numerator/denominator by $\sqrt{2}$

noting that $\sqrt{2}$ × $\sqrt{2}$ = 2

= $\frac{\sqrt{2}(8-3\sqrt{2}) }{\sqrt{2}(\sqrt{2}) }$

= $\frac{8\sqrt{2}-6 }{2}$

Dividing each term on the numerator by 2

= 4 $\sqrt{2}$ - 3

= - 3 + 4 $\sqrt{2}$

with a = - 3 and b = 4

6 0

3 years ago

Read 2 more answers