option A.55°
Answer:
Solution given:
<x+<y=<z
exterior angle of a triangle is equal to the sum of two opposite interior angle
4n-18+n+8=133-6n
5n+6n=133+10
11n=143
n=143/11
n=13
<u>exterior</u><u> </u><u>angle</u><u> </u><u>=</u><u>1</u><u>3</u><u>3</u><u>-</u><u>6</u><u>*</u><u>1</u><u>3</u><u>=</u><u>5</u><u>5</u><u>°</u>
<u>option</u><u> </u><u>A</u><u>.</u><u>5</u><u>5</u><u>°</u>
The area of a trapezpid is 1/2h×(b1+b2)
The longest two sides will be 4 each and the shortest two sides will be 2 each
![\frac{2}{3} x + \frac{1}{6} = -\frac{3}{4} x + 1](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%7D%20x%20%2B%20%20%5Cfrac%7B1%7D%7B6%7D%20%20%3D%20%20-%5Cfrac%7B3%7D%7B4%7D%20x%20%2B%201)
First, simplify
![\frac{2}{3} x](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%7D%20x)
to
![\frac{2x}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2x%7D%7B3%7D%20)
/ Your problem should look like:
Second, simplify
![\frac{3}{4} x](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20x)
to
![\frac{3x}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3x%7D%7B4%7D%20)
/ Your problem should look like:
Third, multiply both sides by 12 (the LCM of 3 and 4) / Your problem should look like:
Fourth, subtract 2 from both sides. / Your problem should look like:
Fifth, simplify -9x + 12 - 2 to -9x + 10. / Your problem should look like:
Sixth, add 9x to both sides. / Your problem should look like:
Seventh, add 8x + 9x to get 17x. / Your problem should look like:
Eighth, divide both sides by 17. / Your problem should look like:
![x = \frac{10}{17}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B10%7D%7B17%7D%20)
Answer as fraction: x =
![\frac{10}{17}](https://tex.z-dn.net/?f=%20%5Cfrac%7B10%7D%7B17%7D%20)
Answer as decimal: x = 0.5882