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Marta_Voda [28]
4 years ago
8

Solve for t a+ct=b+t

Mathematics
1 answer:
Naya [18.7K]4 years ago
3 0
It is 5 bc I’m just answering so I can post my questions
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What is the value of s and the length of side BC if ABCD is a rhombus?
Natali5045456 [20]

Step 1

<u>Find the value of s</u>

we know that

In a Rhombus all sides are congruent

so

AB=BC=CD=DA

AB=9s+29\\CD=10s-16

equate AB and CD

9s+29=10s-16\\

Combine like term

10s-9s=29+16\\

s=45\ units

<u>The answer Part a) is</u>

the value of s is 45\ units

Step 2

<u>Find the value of side AB</u>

AB=9s+29

substitute the value of s

AB=9*45+29=434\ units

Remember that the sides are congruent

AB=BC=CD=DA

therefore

<u>the answer Part b) is</u>

The length of the side BC is 434\ units


4 0
3 years ago
Read 2 more answers
Sry bout the screen,BUT PLEASE HELP!!!!
Tasya [4]

Answer:

40 mph

Step-by-step explanation:

20 miles in 1/2 hour

1/2 times 2 is 1, so 20 times two is 40 mph

7 0
3 years ago
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What is the square root of 789?
Alexeev081 [22]
No even square
28.089
5 0
3 years ago
-5x^2-6=-4x using the Quadratic Formula.
a_sh-v [17]

Answer:

Step-by-step explanation:

-5x² - 6 = -4x

-5x² + 4x - 6 = 0

a = -5  ; b = 4  ; c = -6

Discriminant = b² - 4ac

                     = 4² - 4*(-5)*(-6)

                     = 16 - 120

                     = -104

roots = \dfrac{-b+\sqrt{D}}{2a} \ ; \   \dfrac{-b-\sqrt{D}}{2a}

=\dfrac{-4+\sqrt{-104}}{2*(-5)};\dfrac{-4-\sqrt{-104}}{2*(-5)}\\\\=\dfrac{-4+2i\sqrt{26}}{-10} ; \dfrac{-4-2i\sqrt{26}}{-10}\\\\=\dfrac{(-2)[2-i\sqrt{26}]}{-10} \ ; \ \dfrac{(-2)[2+i\sqrt{26}]}{-10}\\\\=\dfrac{2-i\sqrt{26}}{5} \ ; \ \dfrac{2+i\sqrt{26}}{5}

5 0
3 years ago
A helicopter flew north 325 meters and then flew east 500 meters. How far is the helicopter from its starting point?
kati45 [8]

Answer:

596.34m approx

Step-by-step explanation:

Given data

Let the Starting point be x

A helicopter flew north 325 meters from x

Then flew east 500 meters

Let us apply the Pythagoras theorem to solve for the resultant which is the distance from the starting position

x^2= 325^2+500^2

x^2=105625+250000

x^2= 355625

x= √355625

x=596.34m

Hence the distance from the starting point is 596.34m approx

8 0
3 years ago
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