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Mama L [17]
4 years ago
8

A scientist is studying the light emitted by several celestial objects. He records the shifts in each object’s spectral lines (i

n nm). Based on these measurements, determine whether each object is moving toward or away from Earth. Use the diagram of the visible light spectrum to help you. 400 nm shifted to 430 nm 610 nm shifted to 580 nm 512 nm shifted to 480 nm 670 nm shifted to 690 nm
Physics
1 answer:
forsale [732]4 years ago
5 0

-- 400 nm shifted to 430 nm . . . longer than it should be; "red shifted"; moving away from Earth  

-- 610 nm shifted to 580 nm . . . shorter than at source; "blue shifted"; moving toward Earth

-- 512 nm shifted to 480 nm . . . shorter than at source; moving toward Earth

-- 670 nm shifted to 690 nm . . .longer than at source; moving away from Earth

Now I'd just like to ask one more itty bitty question, that you can think about while you're on this subject:  Astronomers really do this.  They measure how much the wavelength CHANGED, from the time it left the original source until the time they detect it. But HOW do they know what the wavelength WAS when it left the source ? ? ?

THIS is the part that blows my mind !

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Answer:

Part a)

\lambda = 300 m

Part b)

E = 2.7 N/C

Part c)

I = 9.68 \times 10^{-3} W/m^2

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Explanation:

Part a)

As we know that frequency = 1 MHz

speed of electromagnetic wave is same as speed of light

So the wavelength is given as

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Part b)

As we know the relation between electric field and magnetic field

E = Bc

E = (9 \times 10^{-9})(3\times 10^8)

E = 2.7 N/C

Part c)

Intensity of wave is given as

I = \frac{1}{2}\epsilon_0E^2c

I = \frac{1}{2}(8.85 \times 10^{-12})(2.7)^2(3\times 10^8)

I = 9.68 \times 10^{-3} W/m^2

Pressure is defined as ratio of intensity and speed

P = \frac{I}{c} = \frac{9.68\times 10^{-3}}{3\times 10^8}

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<h3>true</h3>

Explanation:

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Nataly_w [17]

Answer:\frac{R}{3}

Explanation:

Given

Sphere of Radius R

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Also by conserving Energy we get

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here h=vertical distance traveled by block

From diagram

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Thus from this value of h is

h=R(1-\sin \theta )

h=R(1-\frac{2}{3})

h=\frac{R}{3}

3 0
4 years ago
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