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Stells [14]
3 years ago
10

Given: Q1 = 3.0 × 10-5 C

Physics
2 answers:
Igoryamba3 years ago
8 0
F=KQ1Q2/R2
F=9 x 10^9 x 3 x 10^-5 x 4 x 10^-5 / 9
F=12 x 10^-1
F=1.2 N
Mariulka [41]3 years ago
4 0
F=k\dfrac{Q_1Q_2}{r^2}= \\  \\ =9\cdot 10^9\cdot \dfrac{3\cdot 10^{-5}\cdot 4\cdot 10^{-5}}{9}=...

You just do the calculations.
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