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Rom4ik [11]
3 years ago
15

I need help on this problem about proofs. I've gotten this far but I'm stuck. Please help me , I suck at math.

Mathematics
1 answer:
laiz [17]3 years ago
6 0

Answer:


Step-by-step explanation:

Givens

DTBC is a rhombus

<RTB = <FCB

Find

RD = DF

Solution

  • <RTB = <FCB             Given
  • TD = DC                     Property of a Rhombus (all four sides are equal)
  • <RDT = <FDC             Vertically opposite angles are equal
  • ΔRDT ≅ ΔFDC           Δ = triangle. The Δs are congruent by ASA.
  • RD = DF                      Parts of congruent triangles are congruent.

You will get problems like the way you were trying to do it. But you should just mark out what you know. I think that you might have forgotten about vertically opposite angles.

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Two angles in a triangle have measures of 13° and 65° what is the measure of the third angle
natulia [17]

Answer:

102

Step-by-step explanation:

All angles added together=180

180-13-65

180-78

102

8 0
3 years ago
Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI
cricket20 [7]

Answer:

The system has infinitely many solutions

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

  1. Switch any two rows
  2. Multiply a row by a nonzero constant
  3. Add one row to another

To solve the following system

\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}

Step 1: Transform the augmented matrix to the reduced row echelon form

\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}

The system has infinitely many solutions.

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

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Answer:

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Step-by-step explanation:

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