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nexus9112 [7]
3 years ago
15

rac{10}{2}" alt="\frac{x}{5} = \frac{10}{2}" align="absmiddle" class="latex-formula">

what is x
Mathematics
1 answer:
bixtya [17]3 years ago
7 0

Answer:

<h3>x =25</h3>

Step-by-step explanation:

<h3>I hope l helped you ❤❤❤</h3>

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A new car is purchased for 23700 dollars. The value of the car depreciates at 13% per year. To the nearest year, how long will i
Lyrx [107]

Answer:

9 years

Step-by-step explanation:

A new car is purchased for 23700 dollars. The value of the car depreciates at 13% per year. To the nearest year, how long will it be until the value of the car is 8000 dollars

8 0
3 years ago
If dy/dx=2xy and y(0)=1.<br> What is y(1) equal to?
Llana [10]

dy/dx = 2xy 
dy/y = (2x)dx 
INT(1/y)dy = INT(2x)dx 
ln y + c = x^2 + d 
ln y = x^2 + constant 
y = e^(x^2 + constant) 

1 = e^constant ... so constant=0 ... so y = e^(x^2) 

Verification: 

y = e^(x^2) 
dy/dx = 2x*e^(x^2) = 2xy 
<span>and e^(0^2) = e^0 = 1


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!</span>
4 0
4 years ago
13. A certain town with a population of 100,000 has 3 newspapers: I, II, and III. The proportions of townspeople who read these
Lina20 [59]

Answer:

24,000 people read only one newspaper

12,000 people read at least two newspapers

11,000 people read at least one morning paper plus an evening paper.

64,000 people do not read any newspapers.

10,000 people read only one morning paper and one evening paper.

Step-by-step explanation:

The problem states that:

- 10 percent of the population reads the newspaper I = 10,000

- 8 percent of the population reads the newspaper I and II = 8,000

- 1 percent of the population reads the newspaper I and II an III = 1,000

- 30 percent of the population reads the newspaper III = 30,000

- 2 percent of the population reads the newspaper I and III = 2,000

- 5 percent of the population reads the newspaper III = 5,000

- 4 percent of the population reads the newspaper II and III = 4,000.

Then we have to build the Venn diagram for this: I am going to call

- A the people that read the newspaper I

- B the people that read the newspaper II

- C the people that read the newspaper III

We start this from the people that read each newspaper

A \cap B \cap C = 1,000 - 1,000 people read each newspaper

The people that read only I and II are the number of people that read I and II minus the number of people that read I, II and III. So:

A \cap B = 8,000 - A \cap B \cap C = 8,000 - 1,000 = 7,000

It applies for I and III

A \cap C = 2,000 - A \cap B \cap C = 2,000 - 1,000 = 1,000

And for II and III

B \cap C = 4,000 - A \cap B \cap C = 4,000 - 1,000 = 3,000

The problem states that 10,000 people read the newspaper I, so:

A + (A \cap B) + (A \cap C) + (A \cap B \cap C) = 10000 where A is the number of people that read only the newspaper I. So:

A + 7,000 + 1,000 + 1,000 = 10,000

A + 9,000 = 10,000

A = 1,000

30,000 read the newspaper II, so:

B + (A \cap B) + (B \cap C) + (A \cap B \cap C) = 30,000

B + 7,000 + 3,000 + 1,000 = 30,000

B + 11,000 = 30,000

B = 19,000

5,000 read the newspaper III, so:

C +  (A \cap C) + (B \cap C) + (A \cap B \cap C) = 5,000

C + 1,000 + 1,000 + 1,000 = 5,000

C = 2,000

The answers:

a) Find the number of people who read only one newspaper

A + B + C = 1,000 + 21,000 + 2,000 = 24,000

24,000 people read only one newspaper

b) How many people read at least two newspapers

(A \cap B) +  (A \cap C) + (B \cap C) + (A \cap B \cap C) = 7,000 + 1,000 + 3,000 + 1,000 = 12,000

12,000 people read at least two newspapers

If I and III are morning papers and II is an evening paper, how many people read at least one morning paper plus an evening paper?

(A \cap B) + (B \cap C) + (A \cap B \cap C) = 7,000 + 3,000 + 1,000 = 11,000

11,000 people read at least one morning paper plus an evening paper.

How many people do not read any newspapers?

There is 100,000 people in the town.

So, the number of people that does not read any newspaper is:

100,000 - (A + B + C + (A \cap B) +  (A \cap C) + (B \cap C) + (A \cap B \cap C)) = 100,000 - 36,000 = 64,000

64,000 people do not read any newspapers.

How many people read only one morning paper and one evening paper?

(A \cap B) + (B \cap C) = 7,000 + 3,000 = 10,000

10,000 people read only one morning paper and one evening paper.

3 0
3 years ago
PLZ HELP: Use Distributive property to create an equal expression:<br><br> 12 j + 12
neonofarm [45]
If the equation is 12 (j + 12) then the answer is 12j + 144
7 0
3 years ago
Which method(s) can be used to solve a system of equations? Select all that apply.
jek_recluse [69]

<u>Out of all given equations, the following methods can be used to solve a system of equations:</u>

  • graphing
  • substitution
  • addition

Answer: Option B, C, and E

<u>Step-by-step explanation:</u>

There are three methods of solving the system of equations as follows:

  • Elimination (addition) method
  • Graphic method
  • Substitution method.

Substitution method: This involves solving one of the variable equations (depending on what you choose) and putting it back into the other equation and "substituting" for the selected variable and resolution for the second. Then solve the first variable again.

Elimination method: This method for solving systems of equations is also known as the addition method. To solve the equation systems by adding or subtracting from the equations to cancel out the common variables

Graphic method: It is used to find a solution to two linear equations. First, expand each equation by “y = ” or replace each equation by y = mx + b. Convert the equations to y = mx + b and prepare a function table.

3 0
3 years ago
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