The greatest common factor of 8x and 22yx is 2x.
I got this answer by factoring out 8 and 22:
8: 1,2,4,8
22: 1,2,11,22
Their greatest common factor was 2 and they both have x.
Your answer is 2x.
Hope this helped! :)
How should people vote paper electronically online arc?
Answer:

96 people in total.
BTW its seats and I think you meant "how many"
Answer: 0
Step-by-step explanation:
The line runs through the coordinate (0,0), rather than starting at (0,2), (0,4), or (0,8).
Always remember that you read coordinates as (x,y) which..
X is how many spaces right or left
Y is how many spaces up or down.
Answer:
A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola
y=5−x^2. What are the dimensions of such a rectangle with the greatest possible area?
Width =
Height =
Width =√10 and Height 
Step-by-step explanation:
Let the coordinates of the vertices of the rectangle which lie on the given parabola y = 5 - x² ........ (1)
are (h,k) and (-h,k).
Hence, the area of the rectangle will be (h + h) × k
Therefore, A = h²k ..... (2).
Now, from equation (1) we can write k = 5 - h² ....... (3)
So, from equation (2), we can write
![A =h^{2} [5-h^{2} ]=5h^{2} -h^{4}](https://tex.z-dn.net/?f=A%20%3Dh%5E%7B2%7D%20%5B5-h%5E%7B2%7D%20%5D%3D5h%5E%7B2%7D%20-h%5E%7B4%7D)
For, A to be greatest ,

⇒ ![h[10-4h^{2} ]=0](https://tex.z-dn.net/?f=h%5B10-4h%5E%7B2%7D%20%5D%3D0)
⇒ 
⇒ 
Therefore, from equation (3), k = 5 - h²
⇒ 
Hence,
Width = 2h =√10 and
Height = 