The third term of the expansion is 6a^2b^2
<h3>How to determine the third term of the
expansion?</h3>
The binomial term is given as
(a - b)^4
The r-th term of the expansion is calculated using
r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)
So, we have
3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)
Evaluate the sum and the difference
3rd term = C(4, 2) * (a)^2 * (-b)^2
Evaluate the exponents
3rd term = C(4, 2) * a^2b^2
Evaluate the combination expression
3rd term = 6 * a^2b^2
Evaluate the product
3rd term = 6a^2b^2
Hence, the third term of the expansion is 6a^2b^2
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<span>According the information given we understand that the room is a regular rectangle, We know that volume = lenght * widht * height, so we start by calculate the room area as length by width, that is 16.4 * 4.5 = 73.8 square metres. Then with 3.26 metres of height, the total volum will 73.8 * 3.26 = 240.58 cubic metres.</span>
Answer:
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Step-by-step explanation:
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Answer:
A
Step-by-step explanation:
The answer is A