Answer:
The child has 6 dimes and 5 quarters.
Step-by-step explanation:
Let q and d represent the number of quarters and of dimes respectively.
Then q + d = 11 (Equation A), and ($0.25/quarter)q + ($0.10/dime)d = $1.85 (Equation B).
Multiply the 2nd equation by 100 to remove the decimal fractions:
25q + 10d = 185 (Equation C)
Now multiply the 1st equation by -10 to obtain -10q - 10d = -110 (Equation D), and combine this result with Equation C:
-10q - 10d = -110
25q + 10d = 185
--------------------------
15q = 75, and so q = 75/15 = 5.
According to Equation A, q + d = 11. Replacing q with 5, we get:
5 + d = 11, and so d = 6.
The child has 6 dimes and 5 quarters.
Answer:
UCL (x bar) = 424
LCL (x bar) = 376
Step-by-step explanation:
Given:
Average calories contained, μ = 400
Standard deviation, σ = 30 calories
Sample size, n = 25
a) UCL (x bar) = 
On substituting the respective values, we get
UCL (x bar) = 
or
UCL (x bar) = 424
Similarly,
LCL (x bar) = 
On substituting the respective values, we get
LCL (x bar) = 
or
LCL (x bar) = 376
Answer: 230. 34 times five is 170. Then you are left with 170 + 3 + 43 + 4 + 3 +4 + 3. You can combine the 3's and you get 9. You are left with 179 + 4 +4 + 43 You combine the 4's and you get 187. 187 + 43 = 230.
multiply all the factors in x^2
to get the roots which are 0, 11/6 and 8/7
