The area of a rectangle is A=LW, the area of a square is A=S^2.
W=S-2 and L=2S-3
And we are told that the areas of each figure are the same.
S^2=LW, using L and W found above we have:
S^2=(2S-3)(S-2) perform indicated multiplication on right side
S^2=2S^2-4S-3S+6 combine like terms on right side
S^2=2S^2-7S+6 subtract S^2 from both sides
S^2-7S+6=0 factor:
S^2-S-6S+6=0
S(S-1)-6(S-1)=0
(S-6)(S-1)=0, since W=S-2, and W>0, S>2 so:
S=6 is the only valid value for S. Now we can find the dimensions of the rectangle...
W=S-2 and L=2S-3 given that S=6 in
W=4 in and L=9 in
So the width of the rectangle is 4 inches and the length of the rectangle is 9 inches.
Answer:
B
Step-by-step explanation:
Since this right angled triangle has two angles of 45, so according to theorem sides opposite to equal angles are equal
Applying Pythagoras theorem
(4√2)^2=(x)^2+(x)^2
32=x^2+x^2
32=2x^2
x^2=32/2
x^2=16
Taking sq root on both sides we get
x=4
Answer:
0 hope it helps ok bye have a good grade
The answer is that his average is 75.5 for the second nine weeks
Answer:
what
Step-by-step explanation: