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2 years ago

I have spent quite long on this but not able to solve it. Pls help ! Thanks!

Mathematics

1 answer:

Elenna [48]2 years ago

4 0

Answer:

Adriana= $960

Tania= $1080

Step-by-step explanation:

Please see the attached pictures for the full solution.

• Do note that you could also use 'x' or other variables to represent the amount of money either Adriana or Tania brought for shopping. A unit was used in this case since I used model method to represent the given situation.

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Find angle x and y. Please show step by step process.

lora16 [44]

Answer:

x = 60, y = 25

Step-by-step explanation:

Δ ABC has 3 congruent sides and is equiangular, thus

the 3 angles are congruent, all 60°

x = 60

∠ ABC and ∠ CBD are adjacent and supplementary, sum to 180° , then

∠ CBD = 180° - 60° = 120°, so

y = 180 - (120 + 35) = 180 - 155 ← sum of angles in triangle

y = 25

4 0

3 years ago

PLS HELP WILL GIVE BRAINLEST AND THANKS!!!!!!!!!!!

Stels [109]

Answer: 2 1/4 more flour for 9 servings

Step-by-step explanation: (a) how many total cups of flour are there per serving? show your work

1 1/2÷6= 3/2 x 1/6 = 3/12= 1/4 cups of flour per serving

(b) how many total cups of sugar (white and brown) are there per serving?show your work

3/4 + 1/3 = 9/12 + 4/12= 13/12= 1 1/12 total cups of sugar

13/12 ÷ 6/1 = 13/12 x1/6 = 13/72 per serving

(c) supposed you modify the recipe so that it makes 9 servings. How much more flour do you need for the modified recipe than you need for the original recipe?Show your work/

1/4 x 9 = 9/4 = 2 1/4 more flour for 9 servings.

8 0

2 years ago

Read 2 more answers

you have to answer 3 essay questions for an exam. there are 6 essays to check choose from. how many different groups of 3 essays

Elis [28]

According to the fundemintal counting princable the answer is 18.

5 0

3 years ago

Find two numbers whose sum is 44 and whose difference is 6.<br> smaller number<br> larger number

Anna [14]

X+ y = 44
x - y = 6
—————
2x = 50

x = 25
y = 44-x = 19

3 0

3 years ago

Sketch the domain D bounded by y = x^2, y = (1/2)x^2, and y=6x. Use a change of variables with the map x = uv, y = u^2 (for u ?

cluponka [151]

Under the given transformation, the Jacobian and its determinant are

$\begin{cases}x=uv\\y=u^2\end{cases}\implies J=\begin{bmatrix}v&u\\2u&0\end{bmatrix}\implies|\det J|=2u^2$

so that

$\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\iint_{D'}\frac{2u^2}{u^2}\,\mathrm du\,\mathrm dv=2\iint_{D'}\mathrm du\,\mathrm dv$

where $D'$ is the region $D$ transformed into the $u$ - $v$ plane. The remaining integral is the twice the area of $D'$ .

Now, the integral over $D$ is

$\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\left\{\int_0^6\int_{x^2/2}^{x^2}+\int_6^{12}\int_{x^2/2}^{6x}\right\}\frac{\mathrm dx\,\mathrm dy}y$

but through the given transformation, the boundary of $D'$ is the set of equations,

$\begin{array}{l}y=x^2\implies u^2=u^2v^2\implies v^2=1\implies v=\pm1\\y=\frac{x^2}2\implies u^2=\frac{u^2v^2}2\implies v^2=2\implies v=\pm\sqrt2\\y=6x\implies u^2=6uv\implies u=6v\end{array}$

We require that $u>0$ , and the last equation tells us that we would also need $v>0$ . This means $1\le v\le\sqrt2$ and $0$ , so that the integral over $D'$ is

$\displaystyle2\iint_{D'}\mathrm du\,\mathrm dv=2\int_1^{\sqrt2}\int_0^{6v}\mathrm du\,\mathrm dv=\boxed6$

4 0

2 years ago