<span>You have:
- The diameter of the cylinder is 12 inches and its height is 14 inches.
-The height of the cone is 6 inches.
So, you must apply the formula for calculate the volume of the cylinder a the formula for calculate the volume of a cone.
V1=</span>πr²h
<span>
V1 is the volume of the cylinder.
r is the radius.
h is the height (h=14 inches)
The problem gives you the diameter, but you need the radius, so you have:
r=D/2
r=12 inches/2
r=6 inches
When you substitute the values into the formula, you obtain:
V1==</span>πr²h
V1=(3.14)(6 inches)²(14 inches)
V1=1582.56 inches³<span>
The volume of the cone is:
V2=(</span>πr²h)/3
<span>
V2 is the volume of the cone.
r is the radius (r=6 inches)
h is the height of the cone (h=6 inches).
Then, you have:
</span>
V2=(πr²h)/3
V2=(3.14)(6 inches)²(6 inches)/3
V2=226.08 inches³
<span>
Therefore, </span>the volume of the cake<span> (Vt) is:
Vt=V1+V2
Vt=</span>1582.56 inches³+226.08 inches³
<span> Vt=1808.6 inches</span>³
Hey there!!
The formula for the area of a square - s²
where s = side
s² = 345
s = √345
s = 18.57 ft
Fence shall be three sides
So 18.57 × 3
The required answer = 55.71 ft
Hope my answer helps!
Answer:
Step-by-step explanation:
When a question asks for the "end behavior" of a function, they just want to know what happens if you trace the direction the function heads in for super low and super high values of x. In other words, they want to know what the graph is looking like as x heads for both positive and negative infinity. This might be sort of hard to visualize, so if you have a graphing utility, use it to double check yourself, but even without a graph, we can answer this question. For any function involving x^3, we know that the "parent graph" looks like the attached image. This is the "basic" look of any x^3 function; however, certain things can change the end behavior. You'll notice that in the attached graph, as x gets really really small, the function goes to negative infinity. As x gets very very big, the function goes to positive infinity.
Now, taking a look at your function, 2x^3 - x, things might change a little. Some things that change the end behavior of a graph include a negative coefficient for x^3, such as -x^3 or -5x^3. This would flip the graph over the y-axis, which would make the end behavior "swap", basically. Your function doesn't have a negative coefficient in front of x^3, so we're okay on that front, and it turns out your function has the same end behavior as the parent function, since no kind of reflection is occurring. I attached the graph of your function as well so you can see it, but what this means is that as x approaches infinity, or as x gets very big, your function also goes to infinity, and as x approaches negative infinity, or as x gets very small, your function goes to negative infinity.
Answer:
x=0
Step-by-step explanation:
solve for x by simplifying both sides of the equation, then isolating the variable. which got me x=0
Answer:
16
Step-by-step explanation:
If x = 4
2(4)+8 (2 * 4 = 8)
8 + 8 = 16
[RevyBreeze]