Question

Last month, he sold 50 chickens and 30 ducks for $550. This month, he sold 44 chickens and 36 ducks for $532. How do you solve this using systems of equations?

Answer 1

Answer: each chicken costs $8.

Each duck costs $5

Step-by-step explanation:

We want to determine the amount for each chicken and each duck.

Let x represent the cost per chicken.

Let y represent the cost per duck.

Last month, he sold 50 chickens and 30 ducks for $550. This is expressed as

50x + 30y = 550- - - - -- - - - - - 1

This month, he sold 44 chickens and 36 ducks for $532. This means that

44x + 36y = 532- - - - - - - - - - - - - 2

Multiplying equation 1 by 44 and equation 2 by 50, it becomes

2200x + 1320y = 24200

2200x + 1800y = 26600

Subtracting, it becomes

- 480y = - 2400

y = - 2400/ - 480

y = 5

Substituting y = 5 into equation 1, it becomes

50x + 30 × 5 = 550

50x + 150 = 550

50x = 550 - 150 = 400

x = 400/50

x = 8

Answer 2

Answer:

sorry im not sure about the answer but this is how you figure it out

Step-by-step explanation:

50a+30b=550

after you simplify = 5a+3b=55

44a+36b=532

after you simplify=11a+9b=133

then you try to find a number

5a+3b=55

then you have to find different possibilities of a and b and if it can fit into both equations then it is correct