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mina [271]
3 years ago
5

$3,804 at 6.1% annual interest for 4 months

Mathematics
1 answer:
Mila [183]3 years ago
4 0
78.13 will be the interest for 4 months  <span />
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Most US adults have social ties with a large number of people, including friends, family, co-workers, and other acquaintances. I
xxTIMURxx [149]

Answer:

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

p_v =2*P(t_{(1699)}>1.971)=0.049  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

Step-by-step explanation:

Data given and notation  

\bar X=669 represent the sample mean

s=732 represent the sample standard deviation

n=1700 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0. represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is different from 634, the system of hypothesis would be:  

Null hypothesis:\mu = 634  

Alternative hypothesis:\mu \neq 634  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=1700-1=1699  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(1699)}>1.971)=0.049  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

3 0
3 years ago
someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your
Lunna [17]

Answer:

Part A) The area of the figure is 24\ units^{2}

Part B) The perimeter of the figure is 20\ units

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

A=\frac{1}{2}bh

<u>Area of triangle ABD</u>

Observing the graph

b=BD=(-2+8)=6\ units

h=(9-5)=4\ units

substitute

A=\frac{1}{2}(6)(4)=12\ units^{2}

<u>Area of triangle BCD</u>

Observing the graph

b=BD=(-2+8)=6\ units

h=(5-1)=4\ units

substitute

A=\frac{1}{2}(6)(4)=12\ units^{2}

The area of the figure is

12\ units^{2}+12\ units^{2}=24\ units^{2}

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

P=AB+BC+CD+AD

we have

A(-5,1),B(-8,5),C(-5,9),D(-2,5)

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Find the distance AB

d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units

Find the distance BC

d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units

Find the distance CD

d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units

Find the distance AD

d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units

substitute the values

P=5+5+5+5=20\ units

7 0
3 years ago
To which graph does the point (−1, 3) belong? y ≥ 2x + 6 y ≥ 3x − 1 y ≥ −x + 3 y ≥ −2x + 5
Anna35 [415]
Well first find the slope of the point
y=mx+b  y=-1x+3
slope = -1
then put the problem in point slope form y - y1 = m (x-x1)
y + 3 = -1 (x+1) then solve for y=mx+b again
so y> 2x + 6 is the answer
4 0
3 years ago
Read 2 more answers
HELP!!!!! I do not understand how to do this! Could someone please explain to me how I would solve this problem?
maks197457 [2]
Yeah man nearly there
3 0
3 years ago
Is y=x^2+7 a linear equation?
tankabanditka [31]

Answer:

No, it is not a linear equation

Step-by-step explanation:

This equation contains the term x², meaning that it is a quadratic function (parabola)

So, it is not a linear equation.

If it were a linear equation, x would not be squared, and the equation would have been in y = mx + b form.

The answer is no, it is not a linear equation.

7 0
3 years ago
Read 2 more answers
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