![\sqrt[3]{x + 1} = 2](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%20%2B%201%7D%20%20%3D%202)
Let us cube both sides.
![= > (\sqrt[3]{x + 1} ) ^{3} = {2}^{3}](https://tex.z-dn.net/?f=%20%3D%20%20%3E%20%20%28%5Csqrt%5B3%5D%7Bx%20%2B%201%7D%20%29%20%5E%7B3%7D%20%20%3D%20%20%7B2%7D%5E%7B3%7D%20)
Now, it will be only x + 1.

Transpose 1 to the Right Hand Side.

Now, subtract.

<u>Answer</u><u>:</u>
x = 7
Hope you could understand.
If you have any query, feel free to ask.
∠Q = ∠R = 47°
answer
<span>∠R
------------------------</span>
Your statement that angle C and angle D adding to 180 degrees isn't always true. What is always true is that angle A and angle C add to 180 degrees.
Rule: The opposite angles of an inscribed quadrilateral are supplementary (add to 180 degrees)
So,
(angle A) + (angle C) = 180
(x+2) + (x-2) = 180
x+2+x-2 = 180
2x = 180
2x/2 = 180/2
x = 90
Once you know x, you can find the angles
measure of angle A = x+2
measure of angle A = 90+2
measure of angle A = 92 degrees
measure of angle C = x-2
measure of angle C = 90-2
measure of angle C = 88 degrees
Note how A+C = 92+88 = 180
measure of angle D = x-10
measure of angle D = 90-10
measure of angle D = 80 degrees
measure of angle B = 360-A-C-D ... see note below
measure of angle B = 360-92-88-80
measure of angle B = 100 degrees
Note: for any quadrilateral, the four angles add to 360 degrees. So A+B+C+D = 360. We can solve for B to get B = 360-A-C-D