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Rom4ik [11]
2 years ago
13

Please what’s the answer?… I really need help

Mathematics
1 answer:
AfilCa [17]2 years ago
3 0

\sqrt[3]{x + 1}  = 2

Let us cube both sides.

=  >  (\sqrt[3]{x + 1} ) ^{3}  =  {2}^{3}

Now, it will be only x + 1.

=  > x + 1 = 8

Transpose 1 to the Right Hand Side.

=  > x = 8 - 1

Now, subtract.

=  > x = 7

<u>Answer</u><u>:</u>

x = 7

Hope you could understand.

If you have any query, feel free to ask.

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nasty-shy [4]

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The answer is

Step-by-step explanation:

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6 0
3 years ago
Someone Help!! 12 points
stiv31 [10]

the answer should be the second one

4 0
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Which equation has the same solution as c^2+6x+1=0
Andreas93 [3]

Answer:

x= -c^2 -1  / 6

Step-by-step explanation:

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7 0
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Answer and explain? I've been getting a lot of these questions wrong lately lol. ​
umka2103 [35]

Answer:

the answer is 31!

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
Which of the following functions is quadratic? f(x)=3(x-4)(x+3), f(x)=5^2, f(x)=2/x, f(x)=2x^3+3x^2-5
DENIUS [597]
In B 5^2 = 25. There is no x anywhere.
In C f(x) = 2/x is a function of a reciprocal, not a quadratic.
In D f(x) = 2x^3 + 3x^2 - 5 is a cubic. A cubic is not a quadratic. The highest power of a quadratic is x^2

That leaves A. When you expand the brackets, you get
3(x^2 + 3x- 4x - 12)
2(x^2 - x - 12) when you remove the brackets you get
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A<<<< answer.
8 0
3 years ago
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