Ask question

Ask question

All categories

Free_Kalibri [48]

3 years ago

11

Anne adds granulated sugar to water and stirs it until all the sugar dissolves, leaving a sweet, transparent liquid. Under which

category should she classify that liquid?

1 answer:

choli [55]3 years ago

4 0

She should be classified under a solevent. Hope this helps

You might be interested in

1. How many metals, nonmetals and metalloids are there in the periodic table?

sweet-ann [11.9K]

Answer:

There are 110 elements known to us, out of which 92 are naturally occurring, while the rest have been prepared artificially. Elements are further classified into metals, non-metals, and metalloids..

Explanation:

Hope it helps you..

Y-your welcome in advance..

(;ŏ﹏ŏ)(ㆁωㆁ)

8 0

3 years ago

A mixture 21.2 g of P and 79.0 g Cl2 reacts completely to form PCl3 and PCl5 as the only products. find the mass of PCl3

IRISSAK [1]

Considering the definition of reaction stoichiometry and limiting reagent, the mass of PCl₃ that could be formed is 38.26 grams.

In first place, you must know that the balanced reaction is:

4 Cl₂ + 2 P → PCl₃ + PCl₅

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Cl₂: 4 moles
P: 2 moles
PCl₃: 1 mole
PCl₅: 1 mole

The molar mass of the compounds is:

Cl₂: 70.9 g/mole
P: 31 g/mole
PCl₃: 137.35 g/mole
PCl₅: 208.25 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Cl₂: 4 moles× 70.9 g/mole = 283.6 grams
P: 2 moles× 31 g/mole= 62 grams
PCl₃: 1 mole× 137.35 g/mole= 137.35 grams
PCl₅: 1mole× 208.25 g/mole= 208.25 grams

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 62 grams of P reacts with 283.6 grams of Cl₂, 21.2 grams of P reacts with how much mass of Cl₂?

$mass of Cl_{2}=\frac{21.2 grams of Px283.6 grams of Cl_{2} }{62 grams of P}$

<u><em>mass of Cl₂= 96.97 grams </em></u>

But 96.97 grams of Cl₂ are not available, 79 grams are available. Since you have less mass than you need to react with 21.2 grams of P, Cl₂ will be the limiting reagent.

Then, it is possible to determine the mass of PCl₃ produced by another rule of three, using the limiting reagent: if by stoichiometry 283.6 grams of Cl₂ produce 137.35 grams of PCl₃, 79 grams of Cl₂ how much mass of PCl₃ will be formed?

$mass of PCl_{3}=\frac{137.35 grams of PCl_{3}x79 grams of Cl_{2} }{283.6grams of Cl_{2}}$

<u><em>mass of PCl₃= 38.26 grams</em></u>

In summary, the mass of PCl₃ that could be formed is 38.26 grams.

Learn more with this examples:

4 0

2 years ago

copper sulphate solution turns the colour of litmus into red but litmus changes into blue with baking soda solution although bot

Bingel [31]

Answer:

Copper sulphate is an acidic salt: It is the product of the reaction between a weak copper base and a strong acid , H2SO4

Litmus has a red colour in acidic solutions:

Conclusion: Acidic copper sulphate solution turns blue litmus to red

Baking soda is a basic salt : It is the reaction product of a weak acid , CO2 and a strong base , NaOH

Litmus has a blue colour in basic solutions:

Conclusion: basic baking soda solution turns red litmus to blue

8 0

3 years ago

What is the atomic number of an atom that has 18 protrons,15 neutrons and 29 electrons?

Artist 52 [7]

Atomic number is same as the protons ...

Soo... the atomic number would be 18

8 0

3 years ago

What is the percent composition of sulfur in H2SO4?

victus00 [196]

<span><span>Percent =mass of the elementx100</span>molar mass of compound</span><span> Find the mass percents for the elements present in H2SO4.molar mass of H2SO4<span> = 2(1) + 32 + 4(16) = 98 g</span><span>mass of H = 2 mol H x 1.008g/mol = 2.016 gmass of S = 1 mol S x 32.00g /mol = 32.00 gmass of O = 4 mol O x 16.00g/mol = 64.00 gmass % H = 2.016g/98g x 100 = 2.06%mass % S = 32.00g/98g x 100 = 32.6%mass % O = 64.00g/98g x 100 = 65.3% </span>Calculate the mass % of the elements present in glucose, C6H12O6. </span>

5 0

3 years ago