Carboxylic acids: considered as weak acids due to they ionize in solution to give -COO⁻ and H⁺, they are abundant in nature, they can form intermolecular hydrogen bonds so they exist as dimers (remember that alcohols also can form hydrogen bonds).
- Acids have higher boiling and melting points than corresponding molar mass compounds due to the formation of hydrogen bond
- Aromatic carboxylic acids are solids in nature at room temperature
Answer:
1. 3.56 M.
2. 0.99 M.
Explanation:
¡Hola!
1. En este caso, dado que la molaridad de una solution es calculada por medio de la siguiente ecuación:

Es posible calcular la molaridad de 50 gramos de hidróxido de potasio primero calculando las moles en dicha masa por medio de la masa molar:

Luego, dado el volumen de la solución, podemos calcular la molaridad:

2. En este segundo ejercicio, procedemos de la misma manera, pues primero calculamos las moles de nitrato de potasio:

Luego, calculamos la molaridad justo como se hizo anteriormente:

Best regards!
Answer:

Explanation:
We must use the Nernst equation

The equation for the cell reaction is is
2Cl⁻(0.384 mol·L⁻¹) + 2Co³⁺(0.324 mol·L⁻¹) ⇌ Cl₂(5.80 atm) + 2Co²⁺(0.158 mol/L)
Data:
E° = 0.483 V
R = 8.314 J·K⁻¹mol⁻¹
T = 25 °C
n = 2
F = 96 485 C/mol
Calculation:
T = 25 + 273.15 = 298.15 K
![Q = \dfrac{\text{[Cl}^{-}]^{2}[\text{Co}^{3+}]^{2}}{p_{\text{Cl}_{2}}^{2}\text{[Co}^{3+}]^{2}} = \dfrac{0.384^{2} \times 0.324^{2}}{5.80 \times 0.158^{2}} =0.1069\\\\E = 0.483 - \left (\dfrac{8.314 \times 298.15 }{2 \times 96485}\right ) \ln(0.1069)\\\\=0.483 -0.01285 \times (-2.236) = 0.483 + 0.02872 = \textbf{0.512 V}\\\text{The cell potential is } \large\boxed{\textbf{0.512 V}}](https://tex.z-dn.net/?f=Q%20%3D%20%5Cdfrac%7B%5Ctext%7B%5BCl%7D%5E%7B-%7D%5D%5E%7B2%7D%5B%5Ctext%7BCo%7D%5E%7B3%2B%7D%5D%5E%7B2%7D%7D%7Bp_%7B%5Ctext%7BCl%7D_%7B2%7D%7D%5E%7B2%7D%5Ctext%7B%5BCo%7D%5E%7B3%2B%7D%5D%5E%7B2%7D%7D%20%3D%20%5Cdfrac%7B0.384%5E%7B2%7D%20%5Ctimes%200.324%5E%7B2%7D%7D%7B5.80%20%5Ctimes%200.158%5E%7B2%7D%7D%20%3D0.1069%5C%5C%5C%5CE%20%3D%200.483%20-%20%5Cleft%20%28%5Cdfrac%7B8.314%20%5Ctimes%20298.15%20%7D%7B2%20%5Ctimes%2096485%7D%5Cright%20%29%20%5Cln%280.1069%29%5C%5C%5C%5C%3D0.483%20-0.01285%20%5Ctimes%20%28-2.236%29%20%3D%200.483%20%2B%200.02872%20%3D%20%5Ctextbf%7B0.512%20V%7D%5C%5C%5Ctext%7BThe%20cell%20potential%20is%20%7D%20%5Clarge%5Cboxed%7B%5Ctextbf%7B0.512%20V%7D%7D)
Answer:
Mass of lava is 8370 g.
Explanation:
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
Symbol:
The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.
Given data:
density of lava = 3.1 g/cm³
volume= 2700 cm³
mass= ?
Solution:
d = m/v
m = d×v
m = 3.1 g/cm³×2700 cm³
m = 8370 g