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Vaselesa [24]
4 years ago
13

Classify the relation according to whether or not they are function

Mathematics
1 answer:
Alenkinab [10]4 years ago
5 0
Please include the relation(s).
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3)3

3 divided by 3 (with the division sign)
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X=2 Y=-4.5 I got this by substituting the value of x into the equation 3(2y+7)-2y=3 and solving.
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For each equation, write a story problem represented by the equation. For each equation, state what quantity x represents.
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X=4
5 0
3 years ago
Read 2 more answers
Can someone help me with this? Its due in 30 minutes and I need help
Stels [109]

Answer:

Quadrants I and II.

O: (-2, 2)

N: (-2, 4)

M: (1, 4)

P: (1, 2)

Step-by-step explanation:

When rotating about the origin 90 degrees in a counterclockwise direction, focus on the coordinates of one point on the preimage at a time. So, the x-coordinate on the image will be the opposite of the y-coordinate of the preimage, and the y coordinate of the image will be the x-coordinate of the preimage. That sounds complicated so here is an example from the problem.

O is a point on the preimage. Its coordinates are (2, 2). To find the x-coordinate, take the opposite of the image's y-coordinate. The y-coordinate is 2, so it will be a -2 x-coordinate on the image. To find the y-coordinate on the image, take the x-coordinate of the preimage (O). The x-coordinate of O is 2, so the y-coordinate of the image will be 2. Combine those together and after a 90 degree counterclockwise rotation, you get a point of (-2, 2)

3 0
3 years ago
Read 2 more answers
Pls help me in this i really need help :( :)
Andrews [41]

Hello and Good Morning/Afternoon:

<u>Let's take this problem step-by-step:</u>

<u>First off, let's write the line in point-slope form:</u>

  \rm \hookrightarrow (y-y_0)=m(x-x_0)

  • (x₀, y₀) any random point on the line
  • 'm' is the value of the slope

<u>Let's calculate the slope:</u>

 \rm \hookrightarrow Slope = \frac{y_2-y_1}{x_2-x_1}

  • (x₁, y₁): any random point on the line                                     ⇒   (-2, -6)
  • (x₂,y₂): any random point on the line that is not (x₁, y₁)         ⇒   (2, -3)

                 \rm \hookrightarrow slope = \frac{-3--6}{2--2} =\frac{3}{4}

<u>Now that we found the slope, let's put it into the point-slope form</u>

  ⇒ we need (x₀, y₀) ⇒ let's use (2,-3)

     (y-(-3))=\frac{3}{4} (x-2)\\y+3=\frac{3}{4} (x-2)

<u>The equation, however, could also be put into 'slope-intercept form'</u>

     ⇒ gotten by isolating the 'y' variable to the left

          y = \frac{3}{4}x-\frac{9}{2}  

<u>Answer:</u>y = \frac{3}{4}x-\frac{9}{2} or y+3=\frac{3}{4} (x-2)

   *<em>Either equations work, put the one that you are the most familiar with</em>

Hope that helps!

#LearnwithBrainly

5 0
2 years ago
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