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Musya8 [376]
3 years ago
5

An alloy has a yield strength of 41 ksi, a tensile strength of 57 ksi, and an elastic modulus of 16 * 106 psi. A cylindrical spe

cimen of this alloy 0.5 in. in diameter and 10 in. long is stressed in tension and found to elongate 0.3 in. On the basis of the information given, is it possible to compute the magnitude of the load that is necessary to produce this change in length
Engineering
1 answer:
-BARSIC- [3]3 years ago
5 0

Answer:

L is beyond tensile strength

so here Hooks law is not valid

Explanation:

given data

yield strength = 41 ksi

tensile strength = 57 ksi

elastic modulus = 16 × 10^{6}  psi

diameter = 0.5 in

stressed in tension = 10 in

elongate = 0.3 in

solution

we will consider here load = L

so now we apply here young's Modulus formula that is

young's Modulus = \frac{stress}{strain}    .................1

young's Modulus = \frac{force/area}{change\ length/ original\ length}    

16 × 10^{6}  = \frac{L*10}{3*3.14*0.25*0.25}

L = 94.2 ksi

so here L is beyond tensile strength

so here Hooks law is not valid

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Answer:

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Explanation:

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<u><em>Deflection angle at B</em></u>

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<u><em>slope at B </em></u>

ΔB = ΔBA = [ 150(6)*3 + 1/2 (300)*6*4 ] / EI

                 = 6300 / ( 500 * 70 ) = 0.18 m = 180 mm

<u><em>Deflection angle at C </em></u>

∅C = ∅CA = [ 1800 + 300*3 ] / EI

                 = 2700 / ( 500 * 70 )

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<u><em>Slope at C </em></u>

ΔC = [ 150 * 6 * 6 + 1/2 (800)*6*7 + 300(3) *1.5 ]

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