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sveticcg [70]
4 years ago
7

What steel type and ASTM designation is preferred for W-shapes?

Engineering
1 answer:
Ulleksa [173]4 years ago
3 0

Answer:

The preferred steel type for W-shapes is structural steel and the its preferred ASTM designation is ASTM A992.

Explanation:

The ASTM A992 is a structural steel and it's the most available for w-shapes; besides its availabilty, its ductility improvements makes it the preferred choice; other common designations for this shapes are ASTM A572 Grade 50,0r ASTM A36, but this designations aren't as available as ASTM A992, and it has to be confirmed prior to their specification.

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Define the coefficient of determination and discuss the impact you would expect it to have on your engineering decision-making b
scoundrel [369]

Answer and Explanation:

The coefficient of determination also called "goodness of fit" or R-squared(R²) is used in statistical measurements to understand the relationship between two variables such that changes in one variable affects the other. The level of relationship or the degree to which one affects the other is measured by 0 to 1 whereby 0 means no relationship at all and 1 means one totally affects the other while figures in between such 0.40 would mean one variable affects 40% of the other variable.

In making a decision as an engineer while using the coefficient of determination, one would try to understand the relationship between variables under consideration and make decisions based on figures obtained from calculating coefficient of determination. In other words when there is a 0 coefficient then there is no relationship between variables and an engineer would make his decisions with this in mind and vice versa.

7 0
4 years ago
A 35 ft long solid steel rod is subjected to a load of 8,000 lb. This load causes the rod to stretch 0.266 in. The modulus of el
solong [7]

Answer:

53.67

Explanation:

3 0
3 years ago
/* Function findBestVacation * duration: number of vacation days * prefs: prefs[k] indicates the rate specified for game k * pla
alexira [117]

Answer:

This is the C++ code for the above problem:

#include<bits/stdc++.h>

using namespace std;

int computeFunLevel(int start, int duration, int prefs[], int ngames, int plan[]) {

if(start + duration > 365) { //this is to check wether duration is more than total no. of vaccation days

return -1;

}

int funLevel = 0;

for(int i=start; i<start+duration; i++) { //this loop runs from starting point till

//start + duration to sum all the funlevel in plan.

funLevel = funLevel + prefs[plan[i]];

}

return funLevel;

}

int findBestVacation(int duration, int prefs[], int ngames, int plan[]) {

int max = 0, index = 0, sum = 0 ;

for(int i=1; i<11; i++){ //this loop is to run through whole plan arry

sum = 0; //sum is initialized with zero for every call in plan ,

//in this case loop should run to 366,but for example it is 11

//as my size of plan array is 11

for(int j=0; j<duration; j++) { // this loop is for that index to index+duration to calc

//fun from that index

sum = sum + prefs[plan[i]];

}

if(sum>max) { //this is to check max funlevel and update the index from which max fun can be achieved

max = sum;

index = i;

}

}

return index;

}

int main() {

int ngames = 5;

int prefs[] = { 1,2,0,5,2 };

int plan[] = { 0,2,0,3,3,4,0,1,2,3,3 };

int start = 1;

int duration = 4;

cout << computeFunLevel(start, duration, prefs, ngames, plan) << endl;

cout << computeFunLevel(start, 555, prefs, ngames, plan) << endl;

cout << findBestVacation(4, prefs, ngames, plan) << endl;

}

The screen of the program is given below.

3 0
3 years ago
Question: 10 of 15
Anvisha [2.4K]

Answer:

Leg length

Explanation:

The distances from the root to the edges of the legs (toes) and the height of the crown are basic measurements.

3 0
3 years ago
In this exercise, you will write a Point structure that represents a space in two-dimensional space. This Point should have both
Afina-wow [57]

Answer:

Check the explanation

Explanation:

Points to consider:

We need to take the input from the user

We need to find the manhatan distance and euclidian using the formula

(x1, y1) and (x2, y2) are the two points

Manhattan:

|x_1 - x_2| + |y_1 - y_2|

Euclidian Distance:

\sqrt{(x1 - yl)^2 + (x2 - y2)^2)}

Code

#include<stdio.h>

#include<math.h>

struct Point{

  int x, y;

};

int manhattan(Point A, Point B){

  return abs(A.x - B.x) + abs(A.y- B.y);

}

float euclidean(Point A, Point B){

  return sqrt(pow(A.x - B.x, 2) + pow(A.y - B.y, 2));

}

int main(){

  struct Point A, B;

  printf("Enter x and Y for first point: ");

  int x, y;

  scanf("%d%d", &x, &y);

  A.x = x;

  A.y = y;

  printf("Enter x and Y for second point: ");

  scanf("%d%d", &x, &y);

  B.x = x;

  B.y = y;

  printf("Manhattan Distance: %d\n", manhattan(A, B));

  printf("Euclidian Distance: %f\n", euclidean(A, B));

 

}

Sample output

8 0
3 years ago
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