Answer:
The solutions for both system of equations are as follows:
- (5,2)
- (2,-1)
Step-by-step explanation:
The first set of equations is:

It can clearly be seen that the coefficients of y are already same in magnitude with different signs so we have to add both equations
So adding both equations, we get

Putting x=5 in equation 1

The solution is (5,2)
The second set of simultaneous equations is:

We can see that the coefficients of x in both equations are same in magnitude with opposite signs so
Adding both equations

Putting y= -1 in first equation

The solution is: (2,-1)
Hence,
The solutions for both system of equations are as follows:
- (5,2)
- (2,-1)
Rule needed: i^2 = -1
Standard form a + bi
(3 + 2i)(7 - 5i) FOIL
3 * 7 = 21
3 * - 5i = - 15i
2i * 7 = 14i
2i * -5i = - 10i^2 = - 10 * -1 = 10
Putting it all back together.
31 - i
Answer:
8
Step-by-step explanation:
- (-2) is the same as + 2
-10 + 2 = -8
I believe it’s AB AND DF, ZBAC = ZDEF