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Ilya [14]
3 years ago
9

Which classification best describes the linear system? Consistent and independent, inconsistent, or coincident

Mathematics
1 answer:
sasho [114]3 years ago
4 0

Answer: I think it's Coincidence.

Step-by-step explanation:

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Which face has an area of 28 cm
Neko [114]

Answer:

trapezium?

Step-by-step explanation:

6 0
3 years ago
A cone with diameter 20 cm and a height of 20 cm. Find the volume of the cone rounded to the nearest tenth.
zhuklara [117]

Answer:

2094.4 cm³

Step-by-step explanation:

The volume of a cone =πr²h/3

Where

r = radius = Diameter/2

Diameter = 20cm, radius = 20cm/2 = 10cm

Height = 20cm

Volume of a cone = π × 10² × 20/3

Volume of a cone = 2094.3951 cm³

Approximately to the nearest tenth = 2094.4 cm³

Therefore , the volume of a cone = 2094.4 cm³

8 0
3 years ago
The difference of the product of 3 and m<br> minus the quotient of m divided by 2<br> m=6
s2008m [1.1K]

Answer:5m/2

Step-by-step explanation:

3m-m/2

(2×3m-1×m)/2

(6m-m)/2=5m/2

5 0
3 years ago
Tim scored 35, 38, and 36 points on three tests. How many points should he get on the fourth test to get an average score of 40?
My name is Ann [436]
I think 51 because if you were to do it reverse then it would be 40x4=160 then -35-36-38 it would be 51.
4 0
3 years ago
A concert hall has 8,000 seats and two categories of ticket prices, $29 and $34. Assume that all seats in each category can be s
Greeley [361]

Using a system of equations, it is found that:

  • For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.
  • For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.
  • For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.

--------------------

The variables of the system are:

  • x, which is the number of $29 tickets sold.
  • y, which is the number of $34 tickets sold.

Total of 8,000 seats, all can be sold, thus:

x + y = 8000 \rightarrow x = 8000 - y

--------------------

For a profit of $255,000, we have that:

29x + 34y = 255000

29(8000 - y) + 34y = 255000

5y = 23000

y = \frac{23000}{5}

y = 4600

x = 8000 - 4600 = 3400

For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.

--------------------

For a profit of $271,000, we have that:

29x + 34y = 271000

29(8000 - y) + 34y = 271000

5y = 39000

y = \frac{39000}{5}

y = 7800

x = 8000 - 7800= 200

For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.

--------------------

For a profit of $235,000, we have that:

29x + 34y = 235000

29(8000 - y) + 34y = 235000

5y = 3000

y = \frac{3000}{5}

y = 600

x = 8000 - 600 = 7400

For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.

A similar problem is given at brainly.com/question/22826010

3 0
3 years ago
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